Answer:
a) 
b)
c)
d)= 0 and the direction of motion is equal to zero
Explanation:
a) compton shift
b) the new wavelength
![=hc[\frac{1}{\lambda'}-\frac{1}{\lambda}]](https://tex.z-dn.net/?f=%3Dhc%5B%5Cfrac%7B1%7D%7B%5Clambda%27%7D-%5Cfrac%7B1%7D%7B%5Clambda%7D%5D)
![\Delta E = 6.626*10^{-34}*(3*10^8)[\frac{1}{14.84*10^{-12}}-\frac{1}{4.8*10^{-12}}]](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%206.626%2A10%5E%7B-34%7D%2A%283%2A10%5E8%29%5B%5Cfrac%7B1%7D%7B14.84%2A10%5E%7B-12%7D%7D-%5Cfrac%7B1%7D%7B4.8%2A10%5E%7B-12%7D%7D%5D)
C)By conservation of energy, the kinetic energy of recoiling electron is equal to the magnitude of energy between the photon energy
d) the angle between the positive direction of motion
= 0
the direction of motion is equal to zero.
Answer:
a) 33.6 min
b) 13.9 min
c) Intuitively, it takes longer to complete the trip when there is current because, the swimmer spends much more time swimming at the net low speed (0.7 m/s) than the time he spends swimming at higher net speed (1.7 m/s).
Explanation:
The problem deals with relative velocities.
- Call Vr the speed of the river, which is equal to 0.500 m/s
- Call Vs the speed of the student in still water, which is equal to 1.20 m/s
- You know that when the student swims upstream, Vr and Vs are opposed and the net speed will be Vs - Vr
- And when the student swims downstream, Vr adds to Vs and the net speed will be Vs + Vr.
Now, you can state the equations for each section:
- distance = speed × time
- upstream: distance = (Vs - Vr) × t₁ = 1,000 m
- downstream: distance = (Vs + Vr) × t₂ = 1,000 m
Part a). To state the time, you substitute the known values of Vr and Vs and clear for the time in each equation:
- (Vs - Vr) × t₁ = 1,000 m
- (1.20 m/s - 0.500 m/s) t₁ = 1,000 m⇒ t₁ = 1,000 m / 0.70 m/s ≈ 1429 s
- (1.20 m/s + 0.500 m/s) t₂ = 1,000 m ⇒ t₂ = 1,000 m / 1.7 m/s ≈ 588 s
- total time = t₁ + t₂ = 1429s + 588s = 2,017s
- Convert to minutes: 2,0147 s ₓ 1 min / 60s ≈ 33.6 min
Part b) In this part you assume that the complete trip is made at the velocity Vs = 1.20 m/s
- time = distance / speed = 1,000 m / 1.20 m/s ≈ 833 s ≈ 13.9 min
Part c) Intuitively, it takes longer to complete the trip when there is current because the swimmer spends more time swimming at the net speed of 0.7 m/s than the time than he spends swimming at the net speed of 1.7 m/s.
The first one is C!
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Answer: It will amount to 11p after 20 years.
Explanation:
Formula :
Simple interest = Principal x rate x Time (i)
Amount = Principal + Interest
Amount = Principal + Principal x rate x Time
Amount = Principal (1+ rate x Time) (ii)
Given: Principal = p
After 1 year , amount = 1.5p
After 3 years , amount = 2.5p
From (ii)
Amount after 20 years = p(1+ 0.5 x 20) = p(1+10)=11p
It will amount to 11p after 20 years.
