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masha68 [24]
3 years ago
10

Someone help me haha;(

Physics
1 answer:
Nikitich [7]3 years ago
6 0

Answer: vf = 51 m/s

d = 112 m

Explanation: Solution attached:

To find vf we use acceleration equation:

a = vf - vi / t

Derive to find vf

vf = at + vi

Substitute the values

vf = 3.5 m/s² ( 8.0 s) + 23 m/s

= 51 m/s

To solve for distance we use

d = (∆v)² / 2a

= (51 m/s - 23 m/s )² / 2 ( 3.5 m/s²)

= (28 m/s)² / 7 m/s²

= 784 m/s / 7 m/s²

= 112 m

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c.5.6m/s^2

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svetlana [45]

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(II). The torque is 84.87 N-m.

Explanation:

Given that,

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Time = 20.0

Distance = 2.5 m

Mass of pole = 4 kg

Angle = 60°

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Using formula of angular velocity

\omega=-\alpha t

\alpha=-\dfrac{\omega}{t}

\alpha=-\dfrac{50.0}{20.0}

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We need to calculate the number of revolution

Using angular equation of motion

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(II). We need to calculate the torque

Using formula of torque

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(II). The torque is 84.87 N-m.

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3 years ago
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