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Nutka1998 [239]
3 years ago
14

Sunny earns $12 per hour delivering cakes. She worked for x hours this week. Unfortunately, she was charged $15 for a late deliv

ery on Tuesday.
How much money did Sunny earn this week?
Write your answer as an expression.
Mathematics
2 answers:
mixas84 [53]3 years ago
8 0
$12 times X - 15

Hope this is right,
xXharleyquinn04Xx
V125BC [204]3 years ago
3 0

Answer:

12x -15 or 12(x) - 15

Step-by-step explanation:

It's 12x -15 because, 12 is the amount of money sunny makes per hour and X is the amount hours she worked in total. Then, if we subtract the $15 late delivery fee, we will end up with an expression like this, 12x -15 or 12(x) - 15. We can't wright it as an equation because there isn't enough information to do so.

I hope this helps,

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Find the value of x for the right triangle. Round your answer to the nearest hundredth
Anna007 [38]

Answer:38.56

Step-by-step explanation:

tan35=opposite ➗ adjacent

0.7002=27 ➗ x

Cross multiplying we get

0.7002(x)=27

Divide both sides by 0.7002

0.7002x ➗ 0.7002=27 ➗ 0.7002

x=38.56041131

x=38.56 nearest hundredth

7 0
3 years ago
Help please I’ll mark brainliest
aleksklad [387]

Answer:

12 miles

Step-by-step explanation:

4*3 =12

7 0
3 years ago
If a test of H subscript 0 colon space mu subscript D equals 0 space v s. space H subscript a colon space space mu subscript D g
lara [203]

Answer:

p_v =P(t_{(n-1)}>t_{calculated}) =0.0601

The p value on this case is given  by the problem.

If we compare the p value with a significance level assumed \alpha=0.05, we see that p_v > \alpha and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value before , y = test value after

The system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x \leq 0

Alternative hypothesis: \mu_y -\mu_x >0

The first step is calculate the difference d_i=y_i-x_i

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=t_{calculated}

The next step is calculate the degrees of freedom given by:

df=n-1

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(n-1)}>t_{calculated}) =0.0601

The p value on this case is given  by the problem.

If we compare the p value with a significance level assumed \alpha=0.05, we see that p_v > \alpha and we can conclude that we FAIL to reject the null hypothesis that the difference mean between after and before is less or equal than 0.

4 0
3 years ago
The height of a rectangle is increasing at a rate of 3 centimeters per hour and the width of the rectangle is decreasing at a ra
n200080 [17]

Answer:

Rate of change of the area of the rectangle at that instant = 7 cm²/hr.

Step-by-step explanation:

Area of rectangle = Height x Width

A = hw

The height of a rectangle is increasing at a rate of 3 centimeters per hour and the width of the rectangle is decreasing at a rate of 4 centimeters per hour.

\texttt{Rate of change of height = }\frac{dh}{dt}=3cm/hr\\\\\texttt{Rate of change of width = }\frac{dw}{dt}=-4cm/hr

Differentiating area with respect to time,

            \frac{dA}{dt}=h\frac{dw}{dt}+w\frac{dh}{dt}

We need to find rate of change of area when the height is 5 centimeters and the width is 9 centimeters.

          \frac{dA}{dt}=h\frac{dw}{dt}+w\frac{dh}{dt}\\\\\frac{dA}{dt}=5\times (-4)+9\times 3=-20+27=7cm^2/hr

Rate of change of the area of the rectangle at that instant = 7 cm²/hr.

5 0
3 years ago
The function j(x)=39x represents the number of jumping jacks j(x) you can do in x minutes. How many jumping jacks can you do in
statuscvo [17]
The function j(x)=39x is the number of jumping jacks you can do in x minutes how many can you do in 5 minutes'?

This is asking you to evaluate the function when x is 5...so all you do here is substitute 5 for x and simplify.. since the question defines "x" as the number of minutes...and j(x) represents the number of jumping jacks.


j(x) = 39x

j(5) = 39(5)

j(5) = 195 <--- answer...


So you do 195 jumping jacks in 5 minutes

I really hope this helps :)
5 0
3 years ago
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