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KIM [24]
3 years ago
5

Base your answer on Betty is thinking of two consecutive integers whose sum is 41.

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

let the numbers be, x and x+1 ( as it is consecutive number the next number will have 1 more than the number )

sum = 41

so, x + ( x + 1 ) = 41

      x + x + 1 = 41

        2x + 1 = 41

             2x = 41 -1 = 40

              2x = 40

                x = 40/2 = 20

x = 20

x + 1 = 20 + 1 = 21

so the consecutive numbers whose sum is 40 are, 20 and 21  

hope this answer helps you.....

please mark as brainliest... thank you!

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Classify each pair of angels listed below as adjacent or vertical.
Stolb23 [73]

Answer:

ntersecting lines DA and CE.

To find:

Each pair of adjacent angles and vertical angles.

Solution:

Adjacent angles are in the same straight line.

Pair of adjacent angles:

(1) ∠EBD and ∠DBC

(2) ∠DBC and ∠CBA

(3) ∠CBA and ∠ABE

(4) ∠ABE and ∠EBD

Vertical angles are opposite angles in the same vertex.

Pair of vertical angles:

(1) ∠EBD and ∠CBA

(2) ∠DBC and ∠EBA

5 0
3 years ago
What is a1 for the geometric sequence for which a8= -3584 and a3 = 112 ?
jasenka [17]

Answer:

The first term is 28.

Step-by-step explanation:

Given: 8th term of Geometric sequence , a_8=-3584

and 3rd term of Geometric Sequence, a_3=112

We have to find First term of given geometric Sequence.

Let a be the first term of geometric sequence.

We know that,

a_n=ar^{n-1}

So,

\frac{a_8}{a_3}=\frac{ar^{8-1}}{ar^{3-1}}=\frac{-3584}{112}

\frac{r^{7}}{r^{2}}=-32

r^5=-32

r=-2

So, a_3=112

a\times(-2)^{2}=112

a=\frac{112}{4}=28

Therefore, The first term is 28.

7 0
3 years ago
Please answer correctly !!!! Will mark Brianliest !!!!!!!!!!!!!
NARA [144]

Answer:

2261,9 cm³

Step-by-step explanation:

First, you need to find the area of the base:

A=\pi r^2

A=36\pi cm²

Now let's multiply it for the height:

36π cm² × 20 cm = 720π cm³

= 2261,9 cm³

5 0
3 years ago
14=2/3c<br><br> what does c equal
pogonyaev

Answer:

1/21

Step-by-step explanation:

14 = 2/3c ➡ 14×3c=2 ➡ 42c = 2➡ c = 1/21

7 0
3 years ago
Read 2 more answers
Euclid and Apollonius stand on two seperate portions which Apollonius 12 meters due worth and 9 meters due East of Euclid. Meanw
Alexeev081 [22]
Draw a diagram to illustrate the problem as shown in the figure below.

Euclid is placed at the origin at (0,0).
Apollonius is 12 m north and 9 m east of Euclid, so its coordinate is (9,12).
Pythagoras is at the arbitrary position (x,y) so that is is at distance d from Euclid and 2d from Apollonius.

From the distance formula, obtain
d² = x² + y²                            (1)
(2d)² = (x-9)² + (y-12)²
or
 4d² = (x-9)² + (y-12)²             (2)

Substitute (1) into (2).
4(x² + y²) = x² - 18x + 81 + y² - 24y + 144
3x² + 3y² + 18x + 24y = 225
Divide by 3.
x² + 6x + y² + 8y = 75
Create perfect squares.
(x+3)² - 9 + (y+4)² - 16 = 75
(x+3)² + (y+4)² = 10²

Answer:
The path of Pythagoras is a circle of radius 10 m, centered at (-3, -4).

8 0
3 years ago
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