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Masteriza [31]
3 years ago
6

Lymphocytes generated during an initial infection that circulate in the body for years and quickly destroy that infection if it

ever appears again are called ______ cells.
Biology
1 answer:
Grace [21]3 years ago
7 0
Lymphocytes generated during an initial infection that circulate in the body for years and quickly destroy that infection if it ever appears again are called the Memory t cells.  These cells are a subset of infection that have previously encountered and responded to their respective antigen, thus they may be called the antigen experienced t cells.
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30% of B-A=18% OF B+A <br>THEN A:B?
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Answer:

1:4

Explanation:

30%= \frac{30}{100}

18%= \frac{18}{100}

<em>Rewrite the given information:</em>

\frac{30}{100} (B - A) =  \frac{18}{100}(B + A)

<em>Multiply by 100 throughout:</em>

30(B -A)= 18(B+A)

<em>Divide by 6 throughout,</em>

5(B -A)= 3(B +A)

<em>Expand</em>

5B -5A= 3B +3A

<em>Bring</em><em> </em><em>A</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>another</em><em>:</em>

5B -3B= 5A +3A

<em>Simplify</em>

2B= 8A

<em>Divide by 2 throughout:</em>

B= 4A

Now, we have to find the ratio of A to B.

B= 4A

<em>Divide by 4 throughout:</em>

A = =  \frac{1}{4} B

<em>Divide by B on both sides:</em>

\frac{A}{B}  =  \frac{1}{4}

Thus, A:B= 1:4

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