Answer:
![\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp](https://tex.z-dn.net/?f=%5Cmu%20_j%3D%5Cdfrac%7B1%7D%7BC_p%7D%5Cleft%20%5BT%5Cleft%28%5Cfrac%7B%5Cpartial%20v%7D%7B%5Cpartial%20T%7D%5Cright%29_p-v%5Cright%5Ddp)
Explanation:
Joule -Thompson effect
Throttling phenomenon is called Joule -Thompson effect.We know that throttling is a process in which pressure energy will convert in to thermal energy.
Generally in throttling exit pressure is low as compare to inlet pressure but exit temperature maybe more or less or maybe remains constant depending upon flow or fluid flow through passes.
Now lets take Steady flow process
Let
Pressure and temperature at inlet and
Pressure and temperature at exit
We know that Joule -Thompson coefficient given as
Now from T-ds equation
dh=Tds=vdp
So
![Tds=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p\right]dp](https://tex.z-dn.net/?f=Tds%3DC_pdt-%5Cleft%20%5BT%5Cleft%28%5Cfrac%7B%5Cpartial%20v%7D%7B%5Cpartial%20T%7D%5Cright%29_p%5Cright%5Ddp)
⇒![dh=C_pdt-\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp](https://tex.z-dn.net/?f=dh%3DC_pdt-%5Cleft%20%5BT%5Cleft%28%5Cfrac%7B%5Cpartial%20v%7D%7B%5Cpartial%20T%7D%5Cright%29_p-v%5Cright%5Ddp)
So Joule -Thompson coefficient
This is Joule -Thompson coefficient for all gas (real or ideal gas)
We know that for Ideal gas Pv=mRT
So by putting the values in
For ideal gas.
Its <span>A. The heat that flows into the system is transformed into work and a change in internal energy</span>
Ultraviolet rays from the sun are very strong, therefore if direct contact is made with skin, it could cause sun burn, or in a worser case skin cancer
Answer:
The initial volume of the system is 2.7 L
Explanation:
The change in internal energy is given by;
ΔU = Q - W
where;
Q is the heat absorb from the surrounding
W is the work done by the system
Given;
ΔU = -107.6 J
Q = 59 J
W = ?
W = Q- ΔU
W = 59J - (-107.6)
W = 166.6 J
Work done is given by;
W = PΔV
W = P(V₂ - V₁)
101.325 Joules = 1 L.atm
166.6 Joules = ?
= 1.644 L.atm
1.644 L.atm = 0.543 atm(57.7L - V₁)
57.7L - V₁ = (1.644 L.atm) / (0.543 atm)
57.7L - V₁ = 3.0 L
V₁ = 57.7L - 3.0 L
V₁ = 2.7 L
Therefore, the initial volume of the system is 2.7 L
Density is equal to mass divided by volume; that said, you would divide 38.6 by 2 to get your answer
