The ideal concept for solving this question is based on the Doppler effect, for which it is indicated that the source's listening frequency changes as the distance and the relative speed between the receiver and the transmitter are also changed. However, if the relative velocity between the two objects is zero as in the particular case presented (since both travel at 75km / h) we have that there will be no change in frequency.
Therefore the frequency that I hear and that my sister would listen would be the same.
Answer:
the force remains constant if the charge does not change
Explanation:
In a capacitor the capacitance is given by
C = ε₀ A / d
Where ε₀ is the permissiveness of emptiness, A is about the plates and d the distance between them.
The charge on the capacitor is given by the ratio
Q = C ΔV
Let's apply these expressions to our problem, if the load remains constant
C = Q / ΔV = ε₀ A / d
ΔV / d = Q / ε₀ A
If the distance increases the capacitance should decrease, therefore if the charge is a constant the voltaje difference must increase
Now we can analyze the force on the test charge in the center of the capacitor
ΔV = E d
E= ΔV/d
F = q E
F = q ΔV / d
Let's replace
F = q Q /ε₀ A
From this expression we see that the force is constant since the voltage increase is compensated by increasing the distance, therefore the correct answer is that the force remains constant if the charge does not change
Answer:
D. momentum
Explanation:
Momentum is the product of velocity and mass which is the two variables the paragraph talked about.
Answer:
this is what I found, hope it helps!
Answer:
3.76
Explanation:
We are given that
Terminal speed in the spread -eagle position,
Terminal speed in the nosedive position,
We have to find the ratio of the effective cross-sectional area A in the slower position to that in the faster position.
We know that
Area, A=
