Answer:
Ultraviolet light has a shorter wavelength than infrared light.
Explanation:
Electromagnetic waves are waves that does nor require material medium for their propagation. Example of Electromagnetic waves are classified according to the acronym RIVUXG. They decrease in wavelength and increase in frequency from Radiowaves to Gamma ray.
R is the Radio waves
U - ultraviolet ray
V - Visible light (ROYGBIV){Red, Orange, Yellow, Green, Blue, Indigo and Violet}
Note that the visible light also decrease in wavelength from red to indigo, therefore red will have longer wavelength compare to blue light.
I - Infrared rays
X - X ray
G - Gamma ray
Based on the above conclusion, it can be inferred that Ultraviolet light has a shorter wavelength than infrared light since Infrared rays comes before the infrared light in the electromagnetic spectrum.
<span>Well, light gathering capacity of a telescope is dependent upon the area of aperture</span>
Answer:
(1) 10^−2 m
Explanation:
The diameter of the tire of an automobile is generally expressed in centimetres; we can say that the diameter of a tire is generally about
d = 20 cm (20 centimetres)
Now we have to verify which option is closest to this value. To do that, we have to keep in mind the equivalence between metres and centimetres; in fact, we have:
This means that we can rewrite the diameter of the tire of a car as
By comparing it with the given options, we see that the closest option is
(1) 10^−2 m
which is therefore the correct answer.
Answer:
P₂ = 2 P₁
we conclude that in the second time the power used is double that in the first rise
Explanation:
In this exercise we are asked the power to climb the stairs, if we assume that we go up with constant speed, we use an energy equal to the potential energy due to the difference in height of the stairs, as this height is constant the potential energy does not change and therefore therefore the energy used by us does not change either.
Now we can analyze the required power,
P = W / t
From the analysis of the previous paragraph the work is equal to the energy used, according to the work energy theorem,
therefore the first time the power is
P₁ = E / 10
P₁ = 0.1 E
for the second time the power is
P₂ = E / 5
P₂ = 0.2 E
we see that the power in the second case is
P₂ = 2 P₁
Therefore, we conclude that in the second time the power used is double that in the first rise.
