Answer:
15.6km
Step-by-step explanation:
Given the map scale 1:200000
1cm on the map represents 200000 cm on ground or in actual distance
Hence, if distance from Belfast to Larne is 7.8vm on map ;
Actual distance will be :
7.8 * 200000 = 1560000 cm
Converting to km :
Recall :
1000 m = 1km
100 cm = 1 m
Hence,
100000 cm = 1km
Therefore, (1560000 / 100000) km
= 15.6km
Hence, distance between Belfast and Larne is 15.6km
Answer:
Step-by-step explanation:
50.
line AB that has the points (2,5) and (9,2) hhas the slope
m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7
Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).
Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or
you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4
51.
line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2
Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5
y-3 = -2/5 (x-1)
Answer:
(x, y ) → (- y, - x )
Step-by-step explanation:
Consider the coordinates of corresponding vertices of the 2 triangles, that is
A(1, 7 ) → D(- 7, - 1 )
Note the coordinates of D are the negative reversals of A
Thus (x, y ) → (- y, - x )
Answer:
Step-by-step explanation:
The prices of quoted of auto repairs are as listed below;
$139, $150, $345, $99, $167, $155, $140, $200.
For her to check whether there is an outlier in the data, she needs to find the mean of the set of data. An outlier is a value in a set of a data that varies considerably from other data in a dataset. It may be larger or smaller than other set of datas. An outlier can affect the decision of a set of data to be analysed if nor taken care of.
From the data, the possible outliers are $99 and $345
Mean of the data = sum of all the prices/sample size
xbar = \sum Xi / N
Xi are individual datas
\sum Xi = $139+$150+$345+$99+$167+$155+$140+$200+$160
\sumXi = $1555
Sample size = 9
Mean = $1555/9
Mean = $172.78
Hence the value that would best represent the central tendency is $177.78
