Need help solving pleaseee!!!

Mathematics

1 answer:

natta225 [31]3 years ago

5 0

Answer:

Step-by-step explanation:

50.

line AB that has the points (2,5) and (9,2) hhas the slope

m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7

Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).

Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or

you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4

51.

line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2

Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5

y-3 = -2/5 (x-1)

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Answer:

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Step-by-step explanation:

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Then, I added the numerators together. Like this:

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<h3>Hope this helps! Let me know if you need help with something else or if you have questions about this problem !</h3>

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