You have defined x to be the smaller of two consecutive integers. Then the larger will be (x+1). The given relation is
... (x) + 3(x+1) = -5 . . . . the smaller plus 3 times the larger is -5
... 4x + 3 = -5 . . . . . . . .simplify
... 4x = -8 . . . . . . . . . . subtract 3
... x = -2 . . . . . . . . . . . divide by the coefficient of x
The smaller of the two integers is -2.
Answer: its the first one bud
Step-by-step explanation:
Answer:
1 question per minute
Step-by-step explanation:
Answer:
y=2(x+2)(x+3)
Step-by-step explanation:
First, we need to factor the right side:
y=2(x^2+5x+6)
Now, we can have an incomplete equation like this:
y=2(x+_)(x+_)
In the blanks, we need to fill out numbers that add to be 5 and multiply to be 6. What are factors of 6? 6 and 1, 2 and 3. Do 6 and 1 add to be 5? No. Do 2 and 3 add to be 5? Yes!
So, our factored form is
y=2(x+2)(x+3)
