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saul85 [17]
3 years ago
10

What digit should go in the box to make the following statement true 63.749<63._2

Mathematics
2 answers:
allochka39001 [22]3 years ago
3 0
The digit should be 8 or 9.
RUDIKE [14]3 years ago
3 0
The digit should be 8 or 9 to make the following statement true.

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Please help which property is illustrated by this example (5 . 15) . 4 = 5 . (15 . 4)
Talja [164]

Answer:

This is the commutative property of multiplication.

Step-by-step explanation:

We know this because that property states that it does not matter what order the numbers are multiplied together, as long as they are all being multiplied. So even though the numbers change on both sides, it does not affect the answer.

4 0
3 years ago
Mr. Pham wrote the equation below on the board.
Margaret [11]

Answer:

x=5.5

Step-by-step explanation:

We can solve this equation by using the various properties and PEMDAS.

First, we would want to subtract 18 on both sides, to even out the equation.

The result is -7x=-38.5

Now we can isolate the x by dividing both sides by -7.

-38/-7=5.5

Thus, x=5.5

Hope this helps!

7 0
3 years ago
Read 2 more answers
1)
Irina-Kira [14]
1. 5x/2 +y=-3 
2. False
3. y= -5x-37  because y=mx-b
4. y= 1/5 x - 1 because y=mx-b  
M= the slope and b represents the intercept.
5 0
3 years ago
Which expression are equivalent to 7•7•7•7•7•7
Natalka [10]
the expression that is equivalent is 7^6*7^1
3 0
3 years ago
Read 2 more answers
Will rate7 you brainliest
Vilka [71]

Answer:

\Large \boxed{\sf \bf \ \ \dfrac{x^2-x-6}{x^2-3x+2} \ \ }

Step-by-step explanation:

Hello, first of all, we will check if we can factorise the polynomials.

\boxed{x^2+6x+8}\\\\\text{The sum of the zeroes is -6=(-4)+(-2) and the product 8=(-4)*(-2), so}\\\\x^2+6x+8=x^2+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)

\boxed{x^2+3x-10}\\\\\text{The sum of the zeroes is -3=(-5)+(+2) and the product -10=(-5)*(+2), so}\\\\x^2+3x-10=x^2+5x-2x-10=x(x+5)-2(x+5)=(x+5)(x-2)

\boxed{x^2+2x-15}\\\\\text{The sum of the zeroes is -2=(-5)+(+3) and the product -15=(-5)*(+3), so}\\\\x^2+2x-15=x^2-3x+5x-15=x(x-3)+5(x-3)=(x+5)(x-3)

\boxed{x^2+3x-4}\\\\\text{The sum of the zeroes is -3=(-4)+(+1) and the product -4=(-4)*(+1), so}\\\\x^2+3x-4=x^2-x+4x-4=x(x-1)+4(x-1)=(x+4)(x-1)

Now, let's compute the product.

\dfrac{x^2+6x+8}{x^2+3x-10}\cdot \dfrac{x^2+2x-15}{x^2+3x-4}\\\\\\=\dfrac{(x+2)(x+4)}{(x+5)(x-2)}\cdot \dfrac{(x+5)(x-3)}{(x+4)(x-1)}\\\\\\\text{We can simplify}\\\\=\dfrac{(x+2)}{(x-2)}\cdot \dfrac{(x-3)}{(x-1)}\\\\\\=\large \boxed{\dfrac{x^2-x-6}{x^2-3x+2}}

So the correct answer is the first one.

Thank you.

7 0
3 years ago
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