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3 years ago

Find hcf and LCM of 40 ,60 and 80

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

Step-by-step explanation:

40 = 2*2*2*5

60 = 2 * 2 * 3 * 5

80= 2 * 2 * 2 * 2 * 5

LCM = 2 * 2 * 2 * 2 * 5 * 3 = 240

HCF = 2*2*5= 20

andre [41]3 years ago

4 0

hear here is your answer in attachment attach

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Answer:

Part a) Exactly values

The width of the rectangle is $\frac{\sqrt{70}}{2}\ cm$

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Part b) Approximately values

The width of the rectangle is $4.2\ cm$

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Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of rectangle is equal to

$A=LW$

we have

$L=4x\ cm\\W=x\ cm$

substitute the values in the formula

$A=4x(x)$

$A=4x^2$

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$70=4x^2$

Solve for x

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square root both sides

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$x=\frac{\sqrt{70}}{2}$

therefore

<em>Exactly values</em>

$L=4\sqrt{70}}{2}=2\sqrt{70}\ cm\\\\W=\frac{\sqrt{70}}{2}\ cm$

<em>Approximately values</em>

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3 years ago

Find hcf and LCM of 40 ,60 and 80​

Find hcf and LCM of 40 ,60 and 80