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3 years ago

Find hcf and LCM of 40 ,60 and 80

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

Step-by-step explanation:

40 = 2*2*2*5

60 = 2 * 2 * 3 * 5

80= 2 * 2 * 2 * 2 * 5

LCM = 2 * 2 * 2 * 2 * 5 * 3 = 240

HCF = 2*2*5= 20

andre [41]3 years ago

4 0

hear here is your answer in attachment attach

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A box of spaghetti at the grocery store is purchased for $1.60 wholesale and is marked up by 60 percent. Then, the store marks d

tester [92]

The first step because 1 dollar and 60 cents is not (1.6)= 2 dollars and 5 cents

5 0

3 years ago

At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive

OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is $\frac{15}{10}$

and in 60 minutes the number of arrival home team fans is $\frac{15 \times 60}{10}$

=90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team leave.

then in 1 minutes $\frac{5}{10}$ fans leave of away team leave.

and In 60 minutes $\frac{5\times 60}{10}$ =30 fans leave of away team leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

4 0

3 years ago

Consider the following 8 numbers, where one labelled X is unknown.

Effectus [21]

Answer:

$55,-3$

Step-by-step explanation:

$We\ are\ given\ that,\\There\ are\ eight\ numbers\ in\ the\ data :\\17,18,24,x,44,48,42,4\\Where\ the\ value\ of\ x\ is\ what\ we\ need\ to\ find.\\Range\ of\ the\ data=51\\Hence,\\We\ know\ that\ the\ range\ is\ the\ difference\\ between\ the\ highest\ observation\ and\ the\ lowest\ observation\ in\ the\ data.\\We\ may\ know\ see\ two\ cases\ of\ evaluating\ x\ when:\\1. x\ is\ the\ highest\ observation\ in\ the\ data\ or\ x>48.\\Highest\ observation\ =x\\Lowest\ observation=4\\Hence,\\$