The equilibrium constant of reaction, usually denoted as K, is a unit of ratio. The ratio involves concentrations of products to reactants. But you also have to incorporate their stoichiometric coefficients in the reaction as their respective exponents. Note that substances in their aqueous state are the ones that are included only in the expression. To properly show you how it's done, consider this equilibrium reaction:
aA (aq) + bB (l) ⇆ nN (aq)
Since only reactant A and product N are aqueous, the equilibrium constant for this reaction is:
K = [N]ⁿ/[A]ᵃ
where the [] brackets denotes concentration in molarity
Now, let's apply this to the given equation:
Cr₂O²⁻ (aq) + 6 I⁻ (aq) + 14 H⁺ (aq) → 3 I₂ (s) + 2 Cr³⁺ (aq) + 7 H₂O<span> (l)
</span>I think there is a typographical error because Cr₂O²⁻ has a negative 2 charge rather than -27. Remember that only substances in aqueous states are included in the K expression. Therefore, the expression for K is:
K = [Cr³⁺]² / [Cr₂O²⁻][I⁻]⁶[H⁺]¹⁴
A. 1:3
The equation shows that 1 mol Fe_3_O4 ≡ 3 mol Fe.
∴ The mole ratio is Fe_3_O4:Fe = 1:3.
“B. 1:4” is <em>incorrect</em>. It is the mole ratio of <em>Fe_3O_4:H_2O </em>and of<em> Fe_3O_4:H_2</em>.
“C: 3:1” is <em>incorrect</em>. It is the mole ratio of <em>Fe:Fe_3O_4</em>.
“D: 4:3” is <em>incorrect</em>. It is the mole ratio of <em>H_2O:Fe and of H_2:Fe</em>.
"<span>Cohesion" is the property of water molecules that leads to high surface tension.
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Surface tension is defined as the energy or the work required to increase the surface area of a liquid as a result of intermolecular forces.
In water molecules, the hydrogen ends, which are positive compared to oxygen ends, cause the water molecules to stick together, thus, increasing its surface tension.
Answer:
12C + 14H₂ + O₂ = 2C₆H₁₃OH .
Explanation:
2,3-dimethyl-1-butanol
= CH₃-CH(CH₃)-CH(CH₃)-CH₂OH.
Molecular formula = C₆H₁₃OH .
= C₆H₁₄O
12C + 14H₂ + O₂ = 2C₆H₁₃OH .
The answer to this question would be: 0.385 j/g°c
Specific heat is the amount of energy needed to increase 1 degree of celcius per one gram of a specific mass. In this question, it needs 83.9 j/°c energy to increase the temperature of 218 g copper. Then, the specific heat would be: (83.9 j/°c) / 218g= 0.38486 j/g°c
