2Al + 3Cl₂ → 2AlCl₃
mol Al = 2/3 x 1.25 = 0.83
mass Al = 0.83 x 27 g/mol = 22.41 g
Answer:
Theoretical yield of vanadium = 1.6 moles
Explanation:
Moles of
= 1.0 moles
Moles of
= 4.0 moles
According to the given reaction:-

1 mole of
react with 5 moles of 
Moles of Ca available = 4.0 moles
Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)
The formation of the product is governed by the limiting reagent. So,
5 moles of Ca on reaction forms 2 moles of V
1 mole of Ca on reaction for 2/5 mole of V
4.0 mole of Ca on reaction for
mole of V
Moles of V = 1.6 moles
<u>Theoretical yield of vanadium = 1.6 moles</u>
Answer:
Hii hello how are you....
The answer is Mg3 glad I helped
Answer:
Explanation:
OK this is simple
i'll try to do the unanswered question
CaCl2
In the table
You look for calcium,Ca you fill 1
THen for Chloride=2
i hope you've understood