What is x-3x-4 but the x is squared to the second power

1 answer:

7 0

Hey! First of all, you can express x squared as x^2.

Secondly, the problem! I'm assuming you're asking for the values of x - if you're asking what the equation is, it's a quadratic equation, or a second-degree polynomial. Solving for x, this equation can be factored as (x-4)(x+1)=0. Because either of these two terms being zero will make the whole equation zero, we can have x-4=0, in which case x=4, or x+1=0, in which case x=-1. Therefore, x is either 4 or -1

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Solve for x. MUST SHOW ALL WORK TO RECEIVE FULL CREDIT! (See picture for equation)

ioda

$\frac{x}{2.4} = \frac{3}{8}$

For proportions and to find x we have to cross multiply
8 × (x) = 3 × 2.4

8x = 7.2
Divide by 8 to isolate x

$\frac{8x}{8} = \frac{7.2}{8}$
8 and 8 cancels out

x = 0.9

5 0

3 years ago

Read 2 more answers

Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7

densk [106]

Answer:

vertical asymptote: x = 7
slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.