The answer is given above
The approximate probability that the code only contains odd numbers is 0.02381.
Answer:
(4,1)
Step-by-step explanation:
let J(6,6) be x1, y1
let K(2,-4) be x2, y2
midpoint = (x1+x2)/2 , (y1+y2)/2
=(6+2)/2 ,(6-4)/2
= 8/2 ,2/2
=4, 1
Answer:
The total cost could be $36
Step-by-step explanation:
36/6 = 6
6 is less than 8
