A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Answer: sale: 536
discount: 33%
33/100*536=
Step-by-step explanation:
1- I assume the cost of the suit is $536, not 536%.
So the % of the part times $536= Original price
Remember, $536 is 77% of the original price.
536x0.77=$696.10
Since the suit was 33% off, and since the sale price of the suit was $536
Then the suit was sold for 67% of its original price
Therefore, 67% of its original price (p) equals $536, or .67(p) = 536
.67p = 536
p = 536 � .67 = $800
Original price of suit was $800
Answer:
(-3,-1)
Step-by-step explanation:
The difference in the x coordinate is 4 and 4 for the y. Add 2 to the x and y from the first coordinate
(-3,-1)
Answer:
d) 0.712
Step-by-step explanation:
Your question isn't clear, so my answer may be wromg
Answer:
T = 4.541
Step-by-step explanation:
We don't have the standard deviation for the population, so we use the t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 4 - 1 = 3
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 4.541
