Hardness is the answer I believe
Answer:
the amount of A was equal to the amount of T
amount of C and the amount of G
Answer:
They have uncoiled to form long, thin strands.
Explanation:
Chromosomes are present in cell nucleus and consist of chromatin. Genes are present in linear order on chromosomes. The chromosomes become visible under the microscope as distinct structures during cell division. When cells are not dividing, the chromosomes decondense to loose their individuality and make the mass of chromatin.
Chromatin is complex of DNA and packing proteins. As the cells enter the prophase stage of cell division, condensation of chromatin occurs and individual chromosomes become visible under microscope. Before that (during interphase), chromosomes are not visible as they are present in decondensed form.
Answer:
Diffusion is the process in which molecules and ions move from a region of high concentration to low concentration. Its also how cells transport waste out of the cell and nutrients into it hence being very crucial. Diffusion also occurs without the expenditure of extra energy using a procedure known as passive transport. (Osmosis is a form of diffusion but deals with water exclusively).
Examples of where diffusion is important;
In the intestines - Digested food molecules such as amino acids and glucose move down the concentration gradient from the intestine into the bloodstream. Wastes such as carbon dioxide or urea travel via diffusion from the body's cells to the bloodstream.
Osmosis plays a major role in living organisms. It aids in the transportation of nutrients from cells to cells and also helps to remove the waste's metabolic products from the cell. The purification of blood in the kidneys is also dependent on the process of osmosis.
Answer:
25%
Explanation:
Let's assume that the recessive allele "p" imparts diseased conditions in the homozygous genotypes. The genotype of each of the carrier parents would be "Pp". A cross between Pp and Pp would produce progeny in the following phenotype ratio=
Pp x Pp= 3/4 Normal : 1/4 Affected.
Therefore, there are 1/4 or 25% chances for this couple to have a child with PKU.
