Because infedecimals. Basically 1 -.99999.... Is a number so close to zero it is impossible to define. If this were infanct the case however and a number existed that was not 0 and not 0 it would wreck mathematics so infedecimals exist only theoretically. So .999... Is equal to 1 practically but not theoretically.
Answer:
10y3 - 5y2 - 10x + 4
————————————————————
2y - 1
Step-by-step explanation:
Step by step solution :
Step 1 :
Equation at the end of step 1 :
Step 2 :
Equation at the end of step 2 :
Step 3 :
10y3 - 5y2 - 10x + 4
Simplify ————————————————————
2y - 1
Checking for a perfect cube :
3.1 10y3 - 5y2 - 10x + 4 is not a perfect cube
Final result :
10y3 - 5y2 - 10x + 4
————————————————————
2y - 1
Divide 400 by 25. You get 16. Multiply 16 by 8. You get 128.
Assuming none of the factors is zero, if an odd number of the factors of a multiplication problem have negative signs, then the product will be negative. Otherwise, the product is positive.
Assuming the dividend of a division problem is non-zero, the quotient wil be negative if the signs of the dividend and divisor are differnt. Otherwise the quotient is positive.
In short, if a multiplication or division problem involves an odd number of minus signs, the result will be negative. Otherwise, the result is positive.
