Answer:
7
Step-by-step explanation:
(a squared) plus (b squared) equals (c squared)
(6 squared) plus (4 squared) equals (c squared)
36+16=c squared
c equals 7
Answer:
32, 46
Step-by-step explanation:
Remember, a is congruent to b modulo d if d divides a-b.
Now, the problem says that b=4 and d=14.
Let a=32. Observe that a-b=28 and 
, then 32 is congruent to 4 modulo 14.
Let a=46. Observe that a-b=46-4=42 and 
, then 46 is congruent to 4 modulo 14.
Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
So we can setup variable equations for this:
so we're given that the length is 22feet longer than the width!
so as an expression length is equal to 22+w
and width as an expression is just w
so the formula for the perimeter for a rectangle is 2l+2w=perimeter
so fill it in now!
1616=2(22+w)+2w
1616=44+2w+2w
1616=44+4w
1572=4w
divide by four..
w=393
and length is simply 22 more than that as stated in the question!
so length is 415
dimensions are: 415x393
<span>8 minutes 20 seconds.
First, lets determine who many miles per minute each vehicle moves by dividing each speed by 60.
Speeder = 60 / 60 = 1 mile per minute.
Police = 75 / 60 = 1.25 miles per minute.
Other car = 45 / 60 = 0.75 miles per minute.
Since the speeding car moves for 5 minutes before the police start to chase, that means that the speeding car will now be 5 + T miles down the road with T being the time the police has been chasing. The police will be 1.25 T. We're looking for when those two equations equal each other. So
5 + T = 1.25 T
Subtract T from both sides
5 = 0.25T
Divide both sides by 0.25
20 = T
So it will take the police officer 20 minutes to catch up to the speeder. And they will both have traveled a total distance of 25 miles from the point where the speeder passed the police car.
Now we need to figure out how far the law obeying car has moved during those 25 minutes. So
25 * 0.75 = 18.75 miles.
The distance the law obeying car needs to travel to catch up to the police officer then becomes
25 - 18.75 = 6.25 miles.
The number of minutes that the law obeying car needs to travel that distance is
6.25 / 0.75 = 8.333....
Which is 8 minutes 20 seconds.</span>
