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Marat540 [252]
3 years ago
5

If the expression f^2+g^4-2f+1 is rewritten in the form a^2+(g^2)^2, what must be the value of a?

Mathematics
1 answer:
sdas [7]3 years ago
6 0

Answer: √(f^2 - 2f + 1) = a

Step-by-step explanation:

We have that:

f^2+g^4-2f+1 =  a^2+(g^2)^2

And we want to find the value of a, so we should isolate it.

f^2 + g^4  - 2f + 1 = a^2 + g^(2*2) = a^2 + g^4

where i used that (x^y)^z = x^(y*z)

We can remove the term g^4 in both sides of the equation and get:

f^2 - 2f + 1 = a^2

now we can apply the square rooth to both sides and get

√(f^2 - 2f + 1) = a

So we just found the value of a.

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A construction manager needs 12 workers to complete a building project in 54 days. Find in terms of T the number of workers need
ch4aika [34]

Answer:

<h3>2T/9</h3>

Step-by-step explanation:

A construction manager needs 12 workers to complete a building project in 54 days, we can write;

12 workers = 54 days

T find the number of workers needed to complete the same project in T days, we will write;

x workers = T days

Divide both equations

12/x = 54/T

Cross multiply

12T = 54x

x = 12T/54

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Hence the number of workers needed to complete the same project in T days is 2T/9 workers

7 0
3 years ago
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0
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Answer:

\frac{-1}{3x^2-x}

Step-by-step explanation:

  1. If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
  2. When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)=\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}

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