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2 years ago

Break apart the number you are subtracting write the different 73-7=

Mathematics

1 answer:

madreJ [45]2 years ago

5 0

The answer is 66..................................................

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It took my question down twice here's a real math question I guess

aliina [53]

Answer:

$n-3$

Interval notation: $(-\infty, -10)\cup(-3,\infty)$

Step-by-step explanation:

First inequality:

$n+8$

Therefore, this inequality restricts:

$n \in \mathrm{R};\: n$

Second inequality:

$< 8+n-3$

Therefore, this inequality restricts:

$n \in \mathrm{R};\: n>-3$

Therefore, with both of these restrictions together, we have:

$\fbox{$n \in \mathrm{R}; n-3$}\\\mathrm{or\:}\fbox{$n-3$}\\\mathrm{or\:}\fbox{$(-\infty, -10)\cup(-3,\infty)$}$ .

4 0

2 years ago

Identify the mapping diagram that represents the relation and determine whether the relation is a function. {(–8, –6), (–5, 2),

SashulF [63]

Do you have the answer options? Sorry, can't answer without them ):

8 0

2 years ago

Read 2 more answers

Find two consecutive odd integers whose sum is 116 (and please have steps) thank you

matrenka [14]

It's 57 and 59
Call (n) is the first odd interger => the second odd interger is (n+2)
=> n + (n + 2) = 116
=> n + n + 2 = 116
=> 2n = 114
=> n = 57
First odd interger is 57 and the second odd interger is 59 .
Sorry my English so bad =)))

6 0

2 years ago

I really need help can somebody please tell me

kotegsom [21]

1-Like Terms
2-Unlike Terms
3-Like terms
4Like Terms
5-Unlike terms
6-Unlike Terms

7 0

2 years ago

Suppose that documentation lists the average sales price of a single-family home in the metropolitan Dallas/Ft. Worth/Irving, Te

Julli [10]

Answer:

"0.0373" seems to be the appropriate solution.

Step-by-step explanation:

The given values are:

n₁ = 43

n₂ = 35

$\bar{x_1}=217800$

$\bar{x_2}=204700$

$\sigma_1=30300$

$\sigma_2=33800$

Now,

The test statistic will be:

⇒ $Z=\frac{\bar{x_1}-\bar{x_2}}\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }$

On substituting the given values in the above formula, we get

⇒ $=\frac{217800-204400}{\sqrt{\frac{(30300)^2}{43} +\frac{(33800)^2}{35} } }$

⇒ $=\frac{217800-204400}{\sqrt{\frac{918090000}{43} +\frac{1142440000}{35} } }$

⇒ $=\frac{13400}{7347.93}$

⇒ $=1.7828$

then,

P-value will be:

= $P(Z>1.7828)$

= $0.0373$

8 0

1 year ago