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OLEGan [10]
3 years ago
12

What does the law of cosines reduce to when dealing with a right triangle

Mathematics
2 answers:
anygoal [31]3 years ago
5 0

Answer:

Pythagorean theorem

Step-by-step explanation:

We know that for a triangle if we know two sides and the included angle, the third side can be found out using cosine formula

a^2=b^2+c^2-2bc cos A

For a right angle triangle right angled at A this becomes

a^2=b^2+c^2-2bc cos A\\=b^2+c^2-2bc cos 90\\=b^2+c^2-0\\=b^2+c^2

This is nothing but Pythagorean theorem

Kamila [148]3 years ago
4 0
<span> The Pythagorean theorem</span>
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If side A is twice as long as B and C is 25 using the Pythagorean Theorem,What are the lengths of side A and B? Round to the nea
777dan777 [17]

Answer:

<u>The lengths of side A is 22.4 and B is 11.9</u>.

Step-by-step explanation:

Given:

If side A is twice as long as B and C is 25 using the Pythagorean Theorem.

Now, to find the lengths of side A and B.

Let the side B be x.

So, the side A be 2x.

Side C = 25.

Now, to solve by using Pythagorean Theorem:

A² + B² = C²

(2x)^2+(x)^2=(25)^2

4x^2+x^2=625

5x^2=625

<em>Dividing both sides by 5 we get:</em>

x^2=125

<em>Using square root on both sides we get:</em>

x=11.18.

<u>B rounding to the nearest tenth =  11.9.</u>

Now, to get A by substituting the value of x:

2x\\=2\times 11.18\\=22.36.

<u>A rounding to the nearest tenth =  22.4.</u>

Therefore, the lengths of side A is 22.4 and B is 11.9.

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