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2 years ago

Help me please!! I will give out brainiest to best answer!!

Mathematics

1 answer:

yawa3891 [41]2 years ago

5 0

So I have the same Prb I did 45 and I did incorrect so what I know. 45 it’s incorrect

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Jenna sells apples and pears. If 20 apples and 60 pears re sold every hour, there will be 80 pears when all the apples are sold.

lutik1710 [3]

Answer:

There are 1,360 pears.

Step-by-step explanation:

Suppose that there are P pears and A apples.

We know that:

"If 20 apples and 60 pears are sold every hour, there will be 80 pears when all the apples are sold."

Suppose that all of these are sold after N hours, then:

20*N = A

80*N = P - 80

We also know that:

"if 60 apples and 20 pears are sold every hour, there will be 400 pears when all the apples are sold."

60*N = A

20*N = P - 400

Then we have four equations:

20*N = A

80*N = P - 80

60*N = A

20*N = P - 400

From the first one and the second one, we get:

20*N = A = 20*N = P - 400

A = P - 400

Now we have 3 equations:

80*N = P - 80

60*N = A

A = P - 400

Now we can just replace the third equation into the second one, then we get:

60*N = A = P - 400

Now we have two equations:

80*N = P - 80

60*N = P - 400

Now, remember that we want to find the number of pears, so we want to find the value of P.

To do it, we can take the quotient of the two equations, so we get:

(80*N)/(60*N) = (P - 80)/(P - 400)

8/6 = (P - 80)/(P - 400)

Now we can solve this for P

(8/6)*(P - 400) = P - 80

(8/6)*P - (8/6)*400 = P - 80

(8/6)*P - P = (8/6)*400 - 80

(2/6)*P = (8/6)*400 - 80

P = (6/2)*( (8/6)*400 - 80 )

P = 3*( (8/6)*400 - 80 ) = 1,360

There are 1,360 pears.

3 0

2 years ago

What is the GCF of 48m5n and 81m2n2

Art [367]

48m^5n: 3*2^4*m^5n

81m^2n^2: 3^4m^2n^2

GCF: 3*m^2n

8 0

3 years ago

A catering service offers

Fiesta28 [93]

Answer:

There are 52920 ways to do the banquet

Step-by-step explanation:

* Lets revise the combination to solve this problem

- A combination is a collection of the objects where the order

doesn't matter

- The order is not important in this problem, so we can use the

combination nCr to find how many ways can this done

* Lets solve the problem

- A catering service offers 6 appetizers, 7 main courses, 10 desserts.

- A customer is to select 5 appetizers, 4 main courses, 5 desserts

for a banquet

∵ We want to select 5 appetizers from 6

∴ There are 6C5 ways to chose the appetizers

∵ 6C5 = 6

∴ There are 6 ways to chose the appetizers

∵ We want to select 4 main courses from 7

∴ There are 7C4 ways to chose the main courses

∵ 7C4 = 35

∴ There are 35 ways to chose the main courses

∵ We want to select 5 desserts from 10

∴ There are 10C5 ways to chose the desserts

∵ 10C5 = 252

∴ There are 252 ways to chose the desserts

- To find the number of ways to do the banquet multiply all the

answers above

∵ The total ways = 6C5 × 7C4 × 10C5

∴ The total ways = 6 × 35 × 252 = 52920

* There are 52920 ways to do the banquet

5 0

2 years ago

Use the parabola tool to graph the quadratic function

aliya0001 [1]

Answer:

That's the graph for the function f(x)= -1/2 x^2 + 7

The vertex is f(0) = 7

5 0

2 years ago

What is the area of a piece of plywood that is 8 2/5 feet by 3 1/8 feet

lesya [120]

The answer would be 26.25

3 0

2 years ago