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ira [324]
3 years ago
13

In △ACD, if AC ≅ AD, m∠A = (3x – 4)°, m∠C = (5x + 1)°, and m∠D = (7x – 27)°, find x and the measure of each angle. *

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0

Answer:

x = 14

A = 38

B = 71

C = 71

Step-by-step explanation:

Since we have a triangle, the addition of the measure of all the measure of the angles give 180

Thus;

3x-4 + 5x + 1 + 7x-27 = 180

15x-30 = 180

15x = 180 + 30

15x = 210

x = 210/15

x = 14

To get the measure of each of the angles, we substitute for x

A = 3x-4 = 3(14) - 4 = 38

B = 5x + 1 = 5(14) + 1 = 70 + 1 = 71

C = 7x - 27 = 7(14) - 27 = 98-27 = 71

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Inside the root is 50-1

50-1 = 49

You would remain with root 49 but, if you calculate the square root the answer would be 7 because...

7•7 = 49


^ So, the answer is 7



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3 years ago
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The cost of 10 days at Healthy Gym is $ .
liq [111]

Answer: $25

Step-by-step explanation:

4 0
3 years ago
Please helppp!! Find the missing side . Round to the nearest tenth
olga nikolaevna [1]

Answer:

7.  7.8

Step-by-step explanation:

We can use Tan of this angle to find the missing side (in this case, the side adjacent to the angle measuring 57°)

 Tan A = (opposite side)/(adjacent side)

    Tan 57° = 12/x

solve for x

           x(Tan 57°) = 12

               x = 12/(Tan 57°)

                 x = 7.8   (rounded to the nearest tenth)

6 0
3 years ago
Please , can someone answer thisss TmT
Tems11 [23]

Answer:

7

Step-by-step explanation:

We have that x1=−1, y1=5, x2=3, y2=7.

Plug the given values into the formula for a slope: m=7−(5)3−(−1)=12.

Now, the y-intercept is b=y1−mx1 (or b=y2−mx2, the result is the same).

b=5−(12)(−1)=112

Finally, the equation of the line can be written in the form y=b+mx:

y=112+x2

ANSWER

5 0
3 years ago
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Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!
kupik [55]

Answer:

The equation of required line is: \mathbf{5x-8y+34=0}

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to 5x-8y+12=0 and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line  5x-8y+12=0 to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: y=mx+b where m is slope.

5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}

So, the slope m = 5/8

The slope of required line is m=\frac{5}{8}

Now finding y-intercept using slope m=\frac{5}{8} and point(-2,3)

y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}

So, the equation of required line having slope m=\frac{5}{8}  and y-intercept b=\frac{17}{4}

y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8}  \\8y=5x+34\\5x-8y+34=0

So, The equation of required line is: \mathbf{5x-8y+34=0}

3 0
2 years ago
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