Write the total number of seeds in scientific notation
Given:
Number of pots = 22,000
Number of seeds = 15
<em>Total number of seeds = Number of pots × Number of seeds</em>
= 22,000 × 15
= 330,000
Scientific notation is written in multiples of 10
- Count the number of digits
- Insert a decimal point between the first digit and other digits
- count the number of digits after the first digits
- multiply by 10 raise to the power of number of remaining digits after first digits
= 3.30000 × 10^5
Therefore,
the total number of seeds in
scientific notation is 3.30000 × 10^5
Read more:
brainly.com/question/10401258
<span>-1 + n=8(n+6)
Use distributive property
-1 + n= 8n + 48
Subtract n from both sides
-1= 7n + 48
Subtract 48 from both sides
-49= 7n
Divide 7 on both sides so that the only thing remaining on the right sides is the varible n.
Final Answer: -7 = n</span>
Answer:
The sixth number in series is 13.
Step-by-step explanation:
Given series : 3, -6, 12, 4, 20, ?
The pattern followed by the series is:
The first number = 3
Second number = 3 - 9 = - 6
Third number = - 6 + (9 ×2) = -6 + 18 = 12
Fourth number = 12 - 8 = 4
Fifth number = 4 + (8 ×2) = 20
Sixth number = 20 - 7 = 13
Seventh number = 13 + (7 ×2) = 13 + 14 = 27 and so on.
So as per the above pattern, the sixth number in the series is 13.
Answer:
yes you can.
Step-by-step explanation:
...
Let
b---> the original amount of blue balls in the bag
p---> the original amount of pink balls in the bag
we know that
b=8+p
p=5
so
b=8+5----> b=13
step 1
Find the total of balls originally in the bag
total =13+5-----> 18
step 2
find <span>the probability that a person will pick a blue ball first
</span>Find P(b)
P (b)=13/18
step 3
Find the probability that a person will pick a pink ball second <span>without replacement
the total of balls now is (18-1)-------> 17
P(p)=5/17
step 4
Find </span><span>the probability that a person will pick a blue ball first and then a pink ball without replacement
</span>(13/18)*(5/17)-----> (13*5)/(18*17)------> 65/306-----> 0.21
the answer is
0.21
