Since these are parabolas with y being squared, the standard form of such a parabola with vertex at (h, k) is
<span>x = a(y - k)^2 + h </span>
<span>There are no steps. Just look at what is inside the parentheses and compare it to (y - k) with k = -3. </span>
<span>Then look at what is added and compare it to h = -1. </span>
<span>For instance, A has (y + 1) in parentheses. So k = -1. And it has -3 added, so h = -3. That would be a vertex at (-3, -1).</span>
Step-by-step explanation:
5x +2 = 182 -4x
5x+4x = 182-2
9x = 180
x = 180/9
x = 20
4y +2 = 5x +2
4y = 5x
4y = 5(20)
4y = 100
y = 100/4
y = 25
Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
I need the 5 summary method for <br>
8, 10, 11, 11, 19, 21, 25, 27, 28, 34, 34, and 38
Masja [62]
Minimum - 8
First Quartile - 11
Median - 23
Third Quartile - 34
Max - 38
Hope this helps!
