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3 years ago

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Find vÌ, the orthogonal projection of v onto w. you can't enter vÌ as a variable name in matlab, so call it vbar instead. also c

ompute z = v - vÌ, the component of v orthogonal to w. then write v as the sum of these two vectors.

1 answer:

lubasha [3.4K]3 years ago

8 0

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A sign company charges $28 per yard for each custom made banner. Ms. Gill orders two banners that are each 1 7/8 yards yards lon

Svetlanka [38]

Answer:

$896

Step-by-step explanation:

We are given that

Charge of 1 yard for each custom-made banner=$28

Length of 1 piece=15 yards

Length of another piece=2 yards

We have to find that how much money payed by Ms.Gill for all three banners.

According to question

Cost of 15 yards long banner=$420

Cost of 2 piece of 15 yards long banner==$840

Cost of 2 yards long banner==$56

Total cost of 3 piece of banners=840+56=$896

Hence, Ms gill pay for all three banners=$896

Your Welcome;)

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3 years ago

Math...need help soon

Kazeer [188]

I don’t know the answer but I noticed you name and saw it. Nice name from shiba.

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2 years ago

If A = 8! and B = 8P8, then which one of the following is true:

meriva

Answer:

A. A = B

Step-by-step explanation:

Given

$A = 8!$

$B = ^8P_8$

Required

Which of the options is true

We start by simplifying $B = ^8P_8$

Permutation is calculated as follows

$^nP_r = \frac{n!}{(n - r)!}$

So.

$^8P_8 =\frac{8!}{(8 - 8)!}$

$^8P_8 =\frac{8!}{0!}$

0! = 1; So

$^8P_8 =\frac{8!}{1}$

$^8P_8 =8!$

Hence. B! = P!

<em>This implies that </em> $A = B = 8!$ <em />

4 0

3 years ago

The quantity r varies jointly with t and u and inversely with s when t= -12, u= -7, and s= -4, r= -126. Find r when t= -8, u= 8,

vichka [17]

Answer:

r = 64

Step-by-step explanation:

r = (k*t*u)/s

Where,

k = constant of proportionality

t = -12,

u= -7,

s= -4,

r= -126.

r = (k*t*u)/s

-126 = (k*-12*-7)/-4

-126 * -4 = 84k

504 = 84k

k = 504/84

k = 6

Find r when t= -8, u= 8, and s= -6.

r = (k*t*u)/s

= (6*-8*8) / -6

= -384 / -6

= 64

r = 64

6 0

3 years ago

Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0

Artyom0805 [142]

Quadratic Formula: $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

$x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}$

Next, solve the exponent and multiplications:

$x=\frac{4\pm \sqrt{16-52}}{2}$

Next, solve the subtraction:

$x=\frac{4\pm \sqrt{-36}}{2}$

Next, factor out i (i = √-1):

$x=\frac{4\pm \sqrt{36}i}{2}$

Next, solve the square root:

$x=\frac{4\pm 6i}{2}$

Lastly, divide and <u>your answer is:</u>

$x=2\pm 3i$

5 0

3 years ago

Read 2 more answers