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3 years ago

10

Carlos used the drawing below to help explain how he found the area of the right triangle. Which expression shows the correct pr

ocess to find the area of the right triangle?

1 answer:

jeka943 years ago

6 0

Answer:

The area of a right-angle triangle is; Area = a x b / 2

Step-by-step explanation:

A right-angle triangle just like conventional triangle, has three sides.

The sides are labelled a, b and c. With a as the height of the triangle and b as the base and c as the slope or the hypotenuse.

The area of a triangle is: (base/2) x height

This is similar to the area of the right-angle triangle which is also half of the base multiplied by the height of the triangle, that is,

Area = ab / 2

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Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

3 years ago

Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre

Lera25 [3.4K]

Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is $\$100.$

The amount deposited in February is $1\$00\times 3= \$300.$

The amount deposited in March is $\$300\times 3= \$900.$

The amount deposited in April is $\$900\times 3= \$2\700.$

The amount deposited in May is $\$2\,700\times 3= \$8\,100.$

The amount deposited in June is $\$8\,100\times 3= \$24\,300.$

Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

$\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400$

5 0

3 years ago

Read 2 more answers

What is -3+5+6g=11-3g solve for g

vitfil [10]

Answer: g = 1

Step-by-step explanation:

-3 + 5 + 6g = 11 - 3g

First, we need to combine like terms

-3 + 5 = 2

2 + 6g = 11 - 3g

Add 3g to each side

2 + 9g = 11

Subtract 2 from each side

9g = 9

Divide each side by 1

g = 1

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3 years ago

Read 2 more answers

Ali has 40 red buttons, 60 green buttons, and 5 blue buttons

mash [69]

Ali must wear a totally ginormous shirt !

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3 years ago

I’ll give the Brainliest!!!

Varvara68 [4.7K]

It’s B hope this helps

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4 years ago