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Sloan [31]
3 years ago
8

What is a short method to show the compound inequality x < 2 AND x > 7

Mathematics
1 answer:
jeyben [28]3 years ago
8 0

These inequalities are not compatible: you are looking for a number that is less than 2, but more than 7. This is impossible, because if a number is less than 2, it can't be more than 7.

Conversely, if a number is more than 7, it can't be less than 2.

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Estimate a 15% tip on a dinner bill of $49.76 by first rounding the bill amount to the nearest ten dollars​
TiliK225 [7]

Answer:

$7.50

Step-by-step explanation:

Round $49.76 to nearest ten dollars =$50.00

15%of $50.00

15/100*50

750/100

$7.50

6 0
3 years ago
Read 2 more answers
Please Help!!!
alekssr [168]
<span>A) About 25% of the fishermen caught between 25 and 30 fish.
 >Since the boxplot looks symmetric, the parts are each 25%. 

</span><span>B) The spread is symmetrical about the median.
 >The median is 20. 
20-15 = 5; 15-10 = 5
25-20 = 5; 30-25 = 5

</span><span>E) The range is 20 fish.
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4 0
3 years ago
2. A(n) _______________ system is a system of equations with an infinite number of solutions.
Anna11 [10]

Answer:

If a system has infinitely many solutions, then the lines overlap at every point. In other words, they're the same exact line! This means that any point on the line is a solution to the system. Thus, the system of equations above has infinitely many solutions.

Step-by-step explanation:

4 0
2 years ago
What is a cube number that us greater than 100 but less that 200
wlad13 [49]
Let the number<span> be H T O. Ones digit = O Given that. O =10−5 ⇒ O =5. Also is given that tens digit T is 2 </span>more than<span> ones digit O ⇒ tens digit T = O +2=5+2=7. ∴ The </span>number<span> is. H 75. Given also is that "</span>number<span> is </span>less<span> than </span>200<span> and </span>greater than 100<span> " ⇒ H can take value only =1. We get our </span>number<span>as 175.</span>
3 0
3 years ago
(a + b)(a ² - ab + b ²) Please help!
kvasek [131]
Hey there :)

( a + b )( a² - ab + b² )
Let us distribute ( a + b )

a ( a² ) + a ( - ab ) + a ( b² ) + b ( a² ) + b ( - ab ) + b ( b² )
a³ - a²b + ab² + a²b - ab² + b³

We can simplify further:
- a²b + a²b = 0
ab² - ab² = 0

a³ + b³

You can see in the picture I have attached that this is the 7th formula

4 0
3 years ago
Read 2 more answers
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