4 years ago

What is a short method to show the compound inequality x < 2 AND x > 7

1 answer:

8 0

These inequalities are not compatible: you are looking for a number that is less than 2, but more than 7. This is impossible, because if a number is less than 2, it can't be more than 7.

Conversely, if a number is more than 7, it can't be less than 2.

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3 years ago

3 + (5 + 4) = 3+ (4 + 5) illustrates which property?

o-na [289]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Picking digits from the list 1, 2, 3, 4, 5, 6, 7, 8, 9 just once, we build two four-digit natural numbers in such a way that the

Ray Of Light [21]

Answer:

3825

Step-by-step explanation:

Given that we have to pick digits from the list 1, 2, 3, 4, 5, 6, 7, 8, 9 just once and build 4 digit numbers.

Find the two numbers which have the sums as the smallest

Since when the two numbers formed are the smallest the sum will be the smallest, we can pick digits in such a ways that the numbers have value the smallest. If the 1000th digit is small we would get smaller number. So let us take for first digit 1000th place 1 and second number 1000th place as 2.

Similarly for 100th now available are 3,4...8, 9 so let us take 100th digit as 3 and 5 respectively and so on.

So the numbers would be

1357 and 2468

Sum would be $1357+2468 = 3825$