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DochEvi [55]
3 years ago
14

What numbers should i put in the drop down menus? the numbers i can choose are 0-9.

Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

1x+4 should be the answer

Step-by-step explanation:

6x-3x-2x=1x

4=4

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Can anyone help me with this?
mestny [16]

Answer:

x = 12

Step-by-step explanation:

they are virtical menaing they are the same value

6x + 7 = 8x - 17

6x + 24 = 8x

24 = 2x

12 = x

8 0
3 years ago
Read 2 more answers
a 5 sided solid has the numbers 1,2,3,4, and 5. what is the probability of rolling two five-sided solids and getting a sum of ei
kipiarov [429]
So this is going to be alot of writing to show my thinking but ill bold the answer.

1,1
1,2
1,3
1,4
1,5

2,1
2,2
2,3
2,4
2,5

3,1
3,2
3,3
3,4
3,5

4,1
4,2
4,3
4,4
4,5

5,1
5,2
5,3
5,4
5,5

next ill mark all the ones that equal 4 or 8 when added together, with an x

1,1
1,2
x1,3
1,4
1,5

2,1
x2,2
2,3
2,4
2,5

x3,1
3,2
3,3
3,4
x3,5

4,1
4,2
4,3
x4,4
4,5

5,1
5,2
x5,3
5,4
5,5

that is 6 (that equal 4 or 8) out of 25

so your ratio would be 6:19
6 0
3 years ago
THREE QUESTIONS PLEASE ANSWER ALL:)
serg [7]
I'm really sorry, but I only know the first question. 

The answer is 340.
8 0
4 years ago
Read 2 more answers
Write the following rational numbers in the standard form. i) −25 - -45
Fiesta28 [93]

Answer:

45-25 or 20 is the answer

7 0
3 years ago
At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. M
m_a_m_a [10]

Answer:

0.7 is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory

Step-by-step explanation:

The two events are independent of each other.

Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal  probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2

Substituting the given values we get

Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =\frac{174}{174 +116} + \frac{20}{180 +20}

=\frac{174}{174 +116} + \frac{20}{180 +20}

== \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7

5 0
3 years ago
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