23<br> (12v + 5)<br> 95<br> Need help!

Find the equation of line (use exact numbers)

maw [93]

Answer:

$y=3x+3$

Step-by-step explanation:

Use the slope-intercept form:

$y=mx+b$

m is the slope and b is the y-intercept. The y-intercept is the place where x is equal to 0, and the slope is the change in the y-axis over the change in the x-axis, otherwise known as rise over run ( $\frac{rise}{run}$ ).

If you study the graph, you can see that the line crosses the y-axis at (0,3), so 3 is the y-intercept. Insert into the formula:

$y=mx+3$

Now find the slope. Use the slope formula:

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{rise}{run}$

You need two points first. You can use the y-intercept (0,3) and another even point, like (1,6). Insert the values:

$(0_{x1},3_{y1})\\(1_{x2},6_{y2})\\\\\frac{6-3}{1-0}=\frac{3}{1}=3$

The slope is 3. Insert this value:

$y=3x+3$

:Done

7 0

3 years ago

If you have four quarters and three nickles how much money do you have

vovangra [49]

Answer:

$1.15

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

You are designing a rectangular poster to contain 7575 in2 of printing with a 33-in margin at the top and bottom and a 11-in m

erma4kov [3.2K]

Answer:

The dimensions of the rectangular poster is 15 in by 5 in.

Step-by-step explanation:

Given that, the area of the rectangular poster is 75 in².

Let the length of the rectangular poster be x and the width of the rectangular poster be y.

The area of the poster = xy in².

$\therefore xy=75$

$\Rightarrow y=\frac{75}{x}$ ....(1)

1 in margin at each sides and 3 in margin at top and bottom.

Then the length of printing space is= (x-2.3) in

=(x-6) in

The width of printing space is = (y-2.1) in

=(y-2) in

The area of the printing space is A =(x-6)(y-2) in²

∴ A =(x-6)(y-2)

Putting the value of y

$\Rightarrow A =(x-6)(\frac{75}{x}-2)$

$\Rightarrow A = 87-\frac{450}{x}-2x$

Differentiating with respect to x

$A '= \frac{450}{x^2}-2$

Again differentiating with respect to x

$A''=-\frac{900}{x^3}$

To find the minimum area of printing space, we set A' = 0

$\therefore \frac{450}{x^2}-2=0$

$\Rightarrow 450 =2x^2$

$\Rightarrow x^2=225$

$\Rightarrow x=\pm 15$

Now putting x=±15 in A''

$A''|_{x=15}=-\frac{900}{15^3}$

$A''|_{x=-15}=-\frac{900}{(-15)^3}=\frac{900}{(15)^3}>0$

Since at x=15 , A"<0 Therefore at x=15 , the area will be minimize.

From (1) we get

$y=\frac{75}{x}$

Putting the value of x

$y=\frac{75}{15}$

=5 in

The dimensions of the rectangular poster is 15 in by 5 in.

4 0

3 years ago

Ali and his father went on a trip to Jazan. Ali drove 52 miles less than his

kenny6666 [7]

Answer:

90

Step-by-step explanation:

divide 292 by 2

subtract 56 to get Ali's and add 56 to his Dad's

I could be wrong it's 6 am

7 0

2 years ago

Will mark brainliest plz help!

Elan Coil [88]

Answer:

56

Step-by-step explanation:

hope it helps

4 0

3 years ago

23 (12v + 5) 95 Need help!