Answer:
1195.22N.
Step-by-step explanation:
Mass: m =82.6 kg
Velocity: v= 16.4m/sec.
Distance: d = 9.29 metres.
Acceleration = (v²/2d) = (16.4²/18.58) = 14.47m/sec².
Force = (mass x acceleration) = (82.6 x 14.47) = 1195.22N.
Answer:
Step-by-step explanation:
Use math-way go quick and easy answers without step by step explanations, and use math-soup-calculator for step by step explanation
Answer:
the required equation is; y = 21 sin(πt/6)
Step-by-step explanation:
Given the data in the question;
Water rises above sea level = 21 ft
Water drops below sea level = 21 ft
so
maximum = 21 ft and also
minimum = 21 ft
Amplitude = ( maximum + minimum ) / 2
Amplitude = ( 21 + 21 ) / 2
Amplitude = ( 21 + 21 ) / 2 = 42/2 = 21 ft
Period = 12 hours
and we know that; period = 2π/b
so
12 = 2π/b
12b = 2π
b = 2π / 12
b = π/6
Standard equation for simple harmonic is; y = asin(bt)
we substitute
y = 21 sin(πt/6)
Hence the required equation is; y = 21 sin(πt/6)
Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
Given:
The quadratic equation is
To find:
The vertex of the given quadratic equation.
Solution:
If a quadratic function is 
, then
We have,
It can be written as
...(i)
Here, 
.
Putting 
in (i), we get
On further simplification, we get
So, the vertex of the given quadratic equation is 
.
Therefore, the correct option is A.
