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Maurinko [17]
3 years ago
7

What is #7 and #8 ?

Mathematics
1 answer:
Ket [755]3 years ago
3 0
So, what is given is the time, and the distance. the distance is equal to the time multiplied by the minute. 
time =t, and distance =d. 
how to get from t to d is 
T divided by 2 multiplied by three equals to D, or T/2 x 3=d.
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Couple more to go, thx for the help >:)
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Answer:  Question 1 is x=9

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Step-by-step explanation:

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The ratio of Pink marbles to white marbles in Samaras bag is equal to 1:5. What percent of the bag contains pink marbles?
EastWind [94]
Think of the contents of the bag having 6 equal parts (in numerical quantity).  Then the fraction of all the marbles which happen to be white marbles is 1/6.  This converts to 16.67%.
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Which number is farthest from 0
Basile [38]

Answer:

17

Step-by-step explanation:

it 17 trust me

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An angle is drawn in standard position passing through the unit circle at (0.643,0.766). The angle in standard position θ has a
Flura [38]
<h2>Hello!</h2>

The asnwer is: Cos50° ≈ 0.643

<h2>Why?</h2>

A unit circle is a cirgle with a radius equal of 1, knowing that,  also know the following:

The angle is drawn passing trough the unit circle at (0.643,0.766) it means that:

x=0.643\\y=0.766

So,

Cos50° ≈ 0.643

We can prove that by following the next steps:

- If it's a unit circle,here is a right triangle with hypotenuse of 1,

1^{2}=x^{2}+y^{2}

1^{2}=0.643^{2}+0.766^{2}

1^{2}=0.4134 +0.5867

1=1.0001=1

- We can determine the cosine of the angle by the following formula:

cos(\alpha)=\frac{x}{hypotenuse} \\cos(\alpha)^{-1}=cos(\frac{0.643}{1})^{-1} \\\alpha=49.98

Therefore,

Cos(α)=49.98°≈50°

Also, if there is a right triangle, according to the Pythagorean Thorem:

1^{2}=(Cos(\alpha))^{2}+(Sin(\alpha))^{2} \\Cos(50)=\sqrt{1-(Sin(50))^{2}}=0.6427

Hence,

Cos50° ≈ 0.643

Have a nice day!

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3 years ago
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Scorpion4ik [409]
The maximum value of that graph is 1 and we can prove this by means of this graph:
http://assets.openstudy.com/updates/attachments/4fe27e44e4b06e92b87169f6-syderitic-1340243754047-unt...

I hope this one works for you
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3 years ago
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