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2 years ago

What type of number is -12 a rational or irrational or integer

Mathematics

1 answer:

Ivanshal [37]2 years ago

8 0

Irrational due to the negative sign

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The function f(x) = x2 - 6x + 9 is shifted 5 units to the left to create g(x). What is g(x)?

creativ13 [48]

Answer:

g(x) = x^2 + 4x + 4

Step-by-step explanation:

In translation of functions, adding a constant to the domain values (x) of a function will move the graph to the left, while subtracting from the input of the function will move the graph to the right.

Given the function;

f(x) = x2 - 6x + 9

a shift 5 units to the left implies that we shall be adding the constant 5 to the x values of the function;

g(x) = f(x+5)

g(x) = (x+5)^2 - 6(x+5) + 9

g(x) = x^2 + 10x + 25 - 6x -30 + 9

g(x) = x^2 + 4x + 4

3 0

2 years ago

Can someone help me with #19

zlopas [31]

Answer:

XZ,X(-10,9)

Y(-4,8)

X2,YZ(14-1)=12

8 0

2 years ago

Samuel drove 84 miles in 6 hours. How far can he drive in 6 hours?

rosijanka [135]

Answer:

the answer is 84 being how you asked the question but I dont think thats what you meant to ask. if thars wrong just tell me and ill answer it the way you need it

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

e-lub [12.9K]

Answer with Step-by-step explanation:

Since the given event is binary we can use Bernoulli's probability to sove the problem

Thus for an event 'E' with probability of success 'p' the probability that the event occurs 'r' times in 'n' trails is given by

$P(E)=\frac{n!}{(n-r)!\cdot r!}\cdot p^{r}\cdot (1-p)^{n-r}$

Part a)

For part a n = 11 , r =9, p = 0.75

Applying values we get

$P(E)=\frac{11!}{(11-9)!\cdot 9!}\cdot (0.75)^{9}\cdot (1-0.75)^{11-9}\\\\\therefore P(E)=0.2581$

Part b)

For part b n = 20 , r = 16 , p=0.75

Applying values we get

$P(E)=\frac{20!}{(20-16)!\cdot 16!}\cdot (0.75)^{16}\cdot (1-0.75)^{20-16}\\\\\therefore P(E)=0.1896$

3 0

3 years ago

Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t

postnew [5]

Hello :
$\left \{ {{x= t^{2} }...(1) \atop {y=2+ 10t }...(2)} \right.$
by(1) :
$t = \frac{y-2}{10}$
subsct in (2) :
$x = ( \frac{y-2}{10} )^{2}$ ....(<span>cartesian equation )</span>

3 0

2 years ago