Answer:
Denote O as center of circle, draw OA, OC.
As property of tangent line from outside of circle (angle OAD = angle OCD = 90 deg):
=> AOC + D = 180
Moreover, angle AOC = 2 x angle B = 2 x 65 = 130
=> D = 180 - 130 = 50 deg
Hope this helps!
:)
Let d=discriminant. The the rule is:
d>0, there are two real solutions
d=0, there is one real solution
d<0, there is no real solutions (but there are two imaginary solutions)
So if it is positive, there are two real solutions.
the series : 6/8 , -1/8 , 2/8 , -24/8 , -4/8 , 8/8
the ascending arrangement : -24/8 , -4/8 , -1/8 , 2/8 , 6/8 , 8/8
=
-3 , -1/2 , -1/8 , |1/4| , 3/4 , |-1|
pls give me brainliest
Do 28+2 which is 30, and then 30/10 which is 3, so 3 equals z
|4x+3|=9+2x if we square both sides, we can eliminate the absolute values signs...
16x^2+24x+9=81+36x+4x^2 subtract the right side from both sides
12x^2-12x-72=0 now we can factor
12(x^2-x-6)=0
12(x^2+2x-3x-6)=0
12(x(x+2)-3(x+2)=0
12(x-3)(x+2)
So:
x= -2 or 3
