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makkiz [27]
3 years ago
11

Anita had $400 in her savings account when she went to college. Her parents will add $200 to her account each month.

Mathematics
2 answers:
Stolb23 [73]3 years ago
6 0
Anita's account had linear growth
Miguel's account had exponential growth.
Miguel's account grew faster because exponential growth is faster than linear growth
Anna007 [38]3 years ago
5 0

Answer:

Miguel's account will grow fast.

Step-by-step explanation:

It is given that:

  • Anita had $400 in her savings account when she went to college. Her parents will add $200 to her account each month.

Let g(t) represents the function that represent the amount of money in Anita's account in 't' months.

Hence, the function g(t) is given by:

g(t)=400+200t

  • Miguel had $25 in his savings account. His parents will double the amount in his account each month.

Let f(t) represents the function that represent the amount of money in Anita's account in 't' months.

Hence, the function g(t) is given by:

f(t)=25\times 2^t

Clearly we could observe that the amount of money in Anita's account have a linear growth and the amount of money in Miguel's account has a exponential growth and we know that exponential function has a more increase i.e. it increases faster than the linear function.

Hence,

Miguel's account will grow fast.

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find the smallest number of terms of the AP "-54,-52.5,-51,-49.5" ....that must be taken for the sum of the terms to be positive
wel

The smallest number of terms of the AP that will make the sum of terms positive is 73.

Since we need to know the number for the sum of terms, we find the sum of terms of the AP

<h3>Sum of terms of an AP</h3>

The sum of terms of an AP is given by S = n/2[2a + (n - 1)d] where

  • n = number of terms,
  • a = first term and
  • d = common difference

Since we have the AP "-54,-52.5,-51,-49.5" ....", the first term, a = -54 and the second term, a₂ = -52.5.

The common difference, d = a₂ - a

= -52.5 - (-54)

= -52.5 + 54

= 1.5

<h3>Number of terms for the Sum of terms to be positive</h3>

Since we require the sum of terms , S to be positive for a given number of terms, n.

So, S ≥ 0

n/2[2a + (n - 1)d] ≥ 0

So, substituting the values of the variables into the equation, we have

n/2[2(-54) + (n - 1) × 1.5] ≥ 0

n/2[-108 + 1.5n - 1.5] ≥ 0

n/2[1.5n - 109.5] ≥ 0

n[1.5n - 109.5] ≥ 0

So, n ≥ 0 or 1.5n - 109.5 ≥ 0

n ≥ 0 or 1.5n ≥ 109.5

n ≥ 0 or n ≥ 109.5/1.5

n ≥ 0 or n ≥ 73

Since n > 0, the minimum value of n is 73.

So, the smallest number of terms of the AP that will make the sum of terms positive is 73.

Learn more about sum of terms of an AP here:

brainly.com/question/24579279

#SPJ1

4 0
2 years ago
A number is picked randomly in the range [0,7]. What is the probability that the number picked is between 3 and 5? What is the p
emmasim [6.3K]

Answer:

(1) 0.125

(2) 0.125

Step-by-step explanation:

The total number of possible outcomes is:

N = 8

(1)

Compute the probability that the number picked is between 3 and 5 as follows:

Number of Favorable outcomes = 1

The probability is:

P (Number picked is between 3 and 5) = 1/8 = 0.125

Thus, the probability that the number picked is between 3 and 5 is 0.125.

(2)

The number usually picked appears to be in in the range [3,5], i.e. the numbers could be, {3, 4 or 5}.

Number of Favorable outcomes = n (Number < 4 and within [3, 5]) = 1

P (less than 4 ∩ within [3, 5]) = 1/8 = 0.125

Thus, the probability that the number picked is less than 4 knowing that the number usually picked appears to be in in the range [3,5] is 0.125.

4 0
3 years ago
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