Remember that the area of a rectangle is the length of the rectangle multiplied by the width of the rectangle.
In this case, we could say (where 
is the area of the rectangle):
Substituting the values the problem gave us for 
and 
, we can find the formula for 
in terms of 
, which is:
The formula for the area of the rectangle would be A(x) = 10x³ - 20x² + 65x.
Answer:
2 sqrt(19)
Step-by-step explanation:
We know that the angle between the two hands
360 /12 *2 = 60 degrees
We divide by 12 because there are 12 number and multiply by 2 because there are 2 number between 10 and 12
This is a triangle where we know 2 sides and the angle between them.
We can use the law of cosines to determine the third side
c^2 = a^2 + b^2 -2abcosC
Where C is the angle between sides a and b
a =4 and b = 10 C = 60 and we are looking for side c
c^2 = 4^2 + 10^2 -2*4*10 cos60
c^2 =16+100 - 80cos 60
c^2 = 76
Take the square root of each side
sqrt(c^2) = sqrt(76)
c = sqrt(76)
c =sqrt(4) sqrt(19)
c =2 sqrt(19)
Answer:
- Initial amount of the material is 67 kg
- Hal-life is 83 hours
<u>The required equation is:</u>
- m(x) = 67 *
, where m- remaining amount of the radioactive material, x - number of hours
<u>After 5 hours the material remains:</u>
- m(5) = 67 *
= 64.260 (rounded)
I’m believe it’s the 3rd one but i’m not sure
Answer:
cos h=x/h=30/g=60/x=rad3/2...y=1/2/z=1
Step-by-step explanation:
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