All categories

2 years ago

How to estimate 1,103 x 59

Mathematics

2 answers:

defon2 years ago

7 0

Answer:

60000

Step-by-step explanation:

Rough estimate: 1000(60) = 60000

shusha [124]2 years ago

6 0

Answer:

1,103~1,000

59~60

×__________________

60000

Step-by-step explanation:

You round each of them by the nearest place then multiply (ex. 12 round the 2 because its the one closest to the highest place ~10

× 15~10=100) sorry if it doesn't make sense @[email protected]

You might be interested in

Solve the system of linear equations by elimination. 12x - 7y = -2 8x + 11y = 30

Sergio039 [100]

Answers: (y = 2) and (x = 1)

Steps:

7 0

3 years ago

The height of a cone is twice the radius of its base.

riadik2000 [5.3K]

Answer:

⅔πx³

Step-by-step explanation:

The formula for the volume of a cone is

V = ⅓πr²h

Let x = radius of base.

Then 2x = height, and

V = ⅓πx²·2x = ⅔πx³

6 0

2 years ago

Please help me with the questions I have please help me with the question mark you as a brnlist

Harlamova29_29 [7]

Answer:

x = 21

Step-by-step explanation:

You can solve this problem by using similar triangles. You can tell that the two triangles are similar by AAA (since two angles are the same, the third must be too).

Now that we've established that the triangles are similar, you need to identify the corresponding sides:

12 corresponds to 28

9 corresponds to x

In order to find x, you'll need to find the scale factor, which you can find by dividing 28 by 12:

28 ÷ 12 = 7/3

Now that you know that 7/3 is the scale factor, you can multiply it by 9 to find x:

9 × 7/3 = x

x = 63/3

x = 21

4 0

2 years ago

What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)

xxMikexx [17]

Let
A------> (5√2,2√3)
B------> (√2,2√3)

we know that
the abscissa and the ordinate are respectively the first and second coordinate of a point in a coordinate system
the abscissa is the coordinate x

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
ABy------> midpoint AB in the coordinate y

ABx=[5√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment is 3√2

see the attached figure