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Tom [10]
3 years ago
8

Help me I didn't learn this lol ╥﹏╥

Mathematics
2 answers:
ivolga24 [154]3 years ago
4 0

Answer:

C.) 60°

Step-by-step explanation:

∠1 = ∠3 and ∠4 = ∠2

so if angle 1 = 55°, so does angle 3.

Therefore, if line y is rotated 5° clockwise, angles 1 and 3 get wider (by 5°).

55 + 5 = 60

∠1 and ∠3 now = 60°

Brainliest please! Hope this helps, good luck.

Rudiy273 years ago
3 0

Answer:

60 degrees

Step-by-step explanation:

This would be the correct answer because angles 1 and 3 are vertical angles so before you move line y, 5 degrees, angle 3 would be 55 degrees too. Since you are moving line y, clockwise, angles 1 and 3 would get bigger by 5 degrees so you would add 5 degrees to 55. 55 + 5 = 60.

So your answer would be 60 degrees.

Hope this helps :)

Maybe brainliest?

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ludmilkaskok [199]

                           

                          Question # 17 Solution

Answer:

x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

Step-by-step Explanation:

The given expression

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

And we have to solve for x₁

So,

Lets solve for x₁.

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Multiply both sides by x₂ - x₁

m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m(x_{2}-x_{1})= (y_{2}-y_{1})

mx_{2}-mx_{1}= (y_{2}-y_{1})

-mx_{1}= y_{2}-y_{1}-mx_{2}

Divide both sides by -m

\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}

x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

Therefore, x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}

                                     Question # 23 Solution

Answer:

n= \frac{bx}{-b + x}

Step-by-step Explanation:

The given expression

\frac{nx}{b}-x=x

And we have to solve for n

So,

Let's solve for n.

\frac{nx}{b}-x=x

Multiply both sides by b.

-bn + nx = bx

Factor out n.

n(-b + x)= bx

Divide both sides by -b + x.

\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}

n= \frac{bx}{-b + x}

Therefore, n= \frac{bx}{-b + x}

<em>Keywords: solution, equation</em>

<em>Learn more about the solution of equations from brainly.com/question/12864981</em>

<em>#learnwithBrainly</em>

6 0
3 years ago
You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

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For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

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schepotkina [342]

Answer: The products are 3 and 6

Step-by-step explanation:

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3 years ago
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