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2 years ago

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A shopper keeper sold a total of 15 boxes of pencils on Monday and Tuesday. She still three more boxes on Monday then on Tuesday

. There were 12 pencils in each box. How many pencils did she sell on Monday?

1 answer:

Nookie1986 [14]2 years ago

8 0

I think 180 that should be your answer sorry i did not get here quick enough

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The total cost (c) in dollars of renting a car for n days is given by the inequality LaTeX: c\ge125+50nc ≥ 125 + 50 n. What is t

zysi [14]

Answer:

<h3>6 days</h3>

Step-by-step explanation:

Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n

To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n

425 ≥ 125 + 50n

Subtract 125 from both sides

425 - 125 ≥ 125 + 50n - 125

300≥ 50n

Divide both sides by 50

300/50≥50n/50

6 ≥n

Rearrange

n≤6

<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>

<em></em>

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2 years ago

Write the Recursive Rule for the sequence:

skad [1K]

A formula is recursive if it expresses the term $a_n$ in terms of the previous one(s) $a_{n-1},\ a_{n-2},\ \ldots,\ a_1$

In this case, every term is 7 more than the previous one, so the formula for $a_n$ will only involve $a_{n-1}$ :

$a_n = a_{n-1} + 7$

In fact, this formula is simply saying: for every index $n$ , the term with that index is 7 more than the term before.

Also, we have to specify the starting point (otherwise we would go backwards indefinitely), so the complete recursive formula is

$a_n = a_{n-1} + 7,\quad a_1 = 2$

which means: start with 2 and generate every other term by adding 7 to the previous one.

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3 years ago

Can you have a triangle with sides 6, 7, and 2?

Alexandra [31]

I believe yes, as long as a triangle has 3 sides it is indeed a triangle

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2 years ago

I need help plzzz this is algebra

SpyIntel [72]

Set like terms on each side by adding six to the first side and subtracting 1/2x from the first side. this gives you 9<1.5x. divide both sides by 1.5 to get 66. the answer is 4) x>6

3 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

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2 years ago