Answer:
Here we have the relation:
m = 140*h
Where m is the distance in miles, and h is time in hours.
And we want to complete a table like:
![\left[\begin{array}{ccc}in, h&out, m\\&\\&\\&\\&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Din%2C%20h%26out%2C%20m%5C%5C%26%5C%5C%26%5C%5C%26%5C%5C%26%5Cend%7Barray%7D%5Cright%5D)
The way to complete this, is to evaluate the function:
m = 140*h
in different values of h, and then record both values of h and m in the table.
Let's use values of h that increase by 0.5, then:
if h = 0.5
m = 140*0.5 = 70
We have the pair: h = 0.5, m = 70
if h = 1
m = 140*1 = 140
We have the pair: h = 1, m = 140
if h = 1.5
m = 140*1.5 = 210
Then we have the pair h = 1.5, m = 210
if h = 2
m = 140*2 = 280
We have the pair: h = 2, m = 280
Now we can complete the table, and it will be:
![\left[\begin{array}{ccc}in, h&out, m\\0.5&70\\1&140\\1.5&210\\2&280\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Din%2C%20h%26out%2C%20m%5C%5C0.5%2670%5C%5C1%26140%5C%5C1.5%26210%5C%5C2%26280%5Cend%7Barray%7D%5Cright%5D)
By taking a look at 1.64, you can already tell the 1 will be the whole number in the fraction. So let's focus on .64.
0.64 is in the hundredths place value, so the denominator will be 100. The unsimplified fraction would be 1 64/100.
To put this in simplest form we must divide 64 and 100. Let's start off with 2.
64/2 = 32
100/2 = 50
Let's continue until we can not divide by 2 anymore.
32/2=16
50/2 = 25
We can no longer divide by 2, howver there is not other number we can divide by both 16 and 25 evenly.
The answer in simplest form is 1 16/25
Answer:
There is nothing there...
Step-by-step explanation:
I wish I could help you but you need to put in a picture or diagram
Answer:
a) m∠T
b) line W and line Z
c) ∠ZTU
d) ∠YTX
e) 90° or m∠5
f) m∠1 and m∠2
g) m∠2
h) 180° or m∠1 & m∠5 or m∠2 & m∠3 & m∠4
i) line WTY and line YTX
j) the angle bisector U
Step-by-step explanation:
