Which organic molecule is found in the chromatin of cells?

What can scientists learn by studying fossils? I. how the Earth's surface has changed over time II. the appearance of an organis

frozen [14]

All of the above!

By analyzing the remains of fossilized organisms (such as old animal bones or plants), scientists can approximate what the organism might have looked like and the climate/environment it lived in -- and based on that, they can try to figure out how the Earth's surface has changed over time. Also, they can use the fossil to compare it to creatures that live now to see what has changed in that species over time.

6 0

4 years ago

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An atom that has 13 protons and 15 neutrons is isotope of the element

wariber [46]

Answer=c

Atoms dont "lose" or "gain" protons, if they did, they'd be completely different elements. So basically, anything with 13 protons is a form of Aluminum.

7 0

3 years ago

Consider the following reaction: 2 Bi(s) + 3 Cl2(g) → 2 BiCl3(s)

Mandarinka [93]

Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Bi + 3 Cl₂ → 2 BiCl₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Bi: 2 moles
Cl₂: 3 moles
BiCl₃: 2 moles

The molar mass of the compounds is:

Bi: 209 g/mole
Cl₂: 70.90 g/mole
BiCl₃: 315.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Bi: 2 moles ×209 g/mole=418 g

Cl₂: 3 moles ×70.90 g/mole= 212.7 g

BiCl₃: 2 moles ×315.45 g/mole= 630.9 g

<h3>Mass of Cl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?

$mass of Cl_{2} =\frac{3.32 grams of BiCl_{3}x212.7 grams of Cl_{2} }{630.9 grams of BiCl_{3}}$