Answer:
The nuclei of most atoms also contain neutrons . The masses of subatomic particles are very tiny. ... Since the nucleus contains protons and neutrons, most of the mass of an atom is concentrated in its nucleus. Protons and electrons have electrical charges that are equal and opposite.
Answer:

Explanation:
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In this case, considering that the density is defined as:

Thus, since 1 kg equals 1000 g and 1 L equal 1000 mL, the required density in g/mL turns out:

Take into account that since 0.65 L has two significant figures, the result is also shown with two significant figures.
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cesium chloride is another chloride that could be used instead of the calcium chloride dihydrate to produce a solid precipitate with aqueous sodium carbonate
A mineral salt called cesium chloride (CsCl) is occasionally ingested or administered intravenously to cancer patients seeking alternative therapies. However, the FDA has not yet approved any cesium chloride products to treat cancer or other disorders.
In isopycnic centrifugation, cesium chloride is a common medical compound used to separate different forms of DNA. It is a reagent used in analytical chemistry to distinguish ions based on the hue and shape of the precipitate.
Cesium chloride is not proven to be effective in treating cancer. As an alternative to chemotherapy for cancer, cesium chloride is pushed. Supporters assert that cesium prevents tumor cells from proliferating by neutralizing the poisons they release.
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A theory fits all three of these descriptions. you can test, predict, and prove or disprove a theory. hope this helps!
Answer:
C20 H14 O2
Explanation:
Remark
This is a sample, which the question does not say and should. It is a fraction of 1 mole. So what you have to do is multiply the numbers given by x and equate it to 286.28
Equation
150,86* x + 8.86*x + 20.1*x = 286.28
179.8x = 286.28
x = 286.26/179.8
x = 1.592
Now multiply the given numbers by 1.592
150.86 * 1.592 = 240.58
8.85 * 1.592 = 14.1
20.1 * 1.592 = 32
Rounding you get
240/12 = 20
14.1/1 = 14
32/16 = 2
C20 H14 O2