1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anastassius [24]
3 years ago
15

Question 18 of 35

Chemistry
1 answer:
sammy [17]3 years ago
4 0

Answer:

A. Dark-colored moths become common after tree trunks become

dark.

Explanation:

I took the test

You might be interested in
1. Water is easily contaminated by both biological and chemical contaminants. Define and give 3 examples of each
tamaranim1 [39]
Are there options like A,B,C,D?

7 0
3 years ago
Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
pochemuha

Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

Now we have to calculate the moles of HCO_3^-.

Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = 37^oC=273+37=310K

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

V=0.51411L=514.11ml

Therefore, the volume of CO_2 will be, 514.11 ml

6 0
3 years ago
What would be the mass of a 33.5dm3 sample of O2 at STP?
liraira [26]

Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

7 0
3 years ago
a hot air balloon has a volume of 875L. what is the original temperature of the balloon if its volume changes to 955 L when heat
soldi70 [24.7K]

Answer:

using Charles law

v1/t1= v2/ t2

Explanation:

875/t1=955/56+273

t1= 329* 875/955

t1= 302.82k

4 0
3 years ago
A point of reference is anything that seems steady that is used compare the position of an object
Masja [62]

Answer:

True

Explanation:

hope it'll help!!

4 0
3 years ago
Read 2 more answers
Other questions:
  • Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu
    11·2 answers
  • Which would result in radioactive decay? Check all that apply.
    5·2 answers
  • What was one idea Dalton taught about atoms?
    10·2 answers
  • ____________________ solids break up into individual neutral particles when dissolved in a solvent.
    15·2 answers
  • What can the size and shape of a sand dune tell you about how it was formed?
    9·1 answer
  • Determine what elements are denoted by the following electron configurations:
    11·1 answer
  • 10. Which of the following group of colors of the visible light is listed from
    11·1 answer
  • What process at the surface of the Earth is part of the formation of sedimentary rocks?
    9·1 answer
  • What are the oxidation numbers for groups 1-18 (skip groups 3-12)
    6·2 answers
  • Please please do it because i need an answer.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!