Answer:
Scale factor for the drawing from actual park = 
Area of the actual park = 1200 cm²
Step-by-step explanation:
Length of the rectangular city park = 5 cm
Width of the rectangular park = 6 cm
Using scale factor 1 cm = 20 meters
Scale factor = 

Actual length = 5 × 20 = 100 meters
Actual width = 6 × 20 = 120 meters
Area of the rectangular park = length × width
= 100 × 120
= 1200 square meters
Therefore, Scale factor from actual length to the length in drawing = 1 : 20
Area of the rectangular park = 1200 square feet
Answer:

Step-by-step explanation:
We have been given an equation
. We are asked to solve our given equation.
First of all, we will add
on both sides of equation to separate x variable on one side of equation.


Now, we will make a common denominator.


Add numerators:


Upon multiply both sides of our equation by
, we will get:



Therefore, the solution for our given equation is
.
Pick 2 pairs of equations t<span>hen use addition and subtraction to eliminate </span>the same variable<span> from both pairs of equations then it is left with 2 variables
</span>Pick two pairs
<span><span>4x - 3y + z = - 10</span><span>2x + y + 3z = 0
</span></span>eliminate the same variable from each system
<span><span>4x - 3y + z = - 10</span>
<span>2x + y + 3z = 0</span>
<span>4x - 3y + z = - 10</span>
<span>-4x - 2y - 6z = 0</span>
<span>-5y - 5z = - 10</span>
<span>2x + y + 3z = 0</span>
<span>- x + 2y - 5z = 17</span>
<span>2x + y + 3z = 0</span>
<span>-2x + 4y - 10z = 34</span>
<span>5y - 7z = 34
</span></span>Solve the system of the two new equations:
<span><span>-5y - 5z = - 10</span>
<span>5y - 7z = 34</span>
<span>-12z = 24</span>
which is , <span>z = - 2</span>
<span>-5y - 5(- 2) = - 10</span>
<span>-5y = - 20</span>
wich is , <span>y = 4
</span></span>substitute into one of the original equations
<span>- x + 2y - 5z = 17</span>
<span>- x + 2(4) - 5(- 2) = 17</span>
<span>- x + 18 = 17</span>
<span>- x = - 1</span>
<span>x = 1</span>
<span>which is , </span><span>(x, y, z) = (1, 4, - 2)</span><span>
</span>Does 2(1) + 4 + 3(- 2) = 0<span> ? Yes</span><span>
</span>
Answer:
Area of a trapezoid is found with the formula, A=(a+b)/2 x h
Step-by-step explanation: