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ki77a [65]
2 years ago
13

The width of a rectangle is 7 meters greater than its length. If the area of the rectangle is 170 square meters, write the quadr

atic equation in standard form for the equation that would represent the area of the rectangle. Let x equal the length of the rectangle.
Mathematics
1 answer:
Taya2010 [7]2 years ago
6 0

Answer: The quadratic equation in standard form for the equation that would represent the area of the rectangle is

x^2 + 7x- 170 = 0

Step-by-step explanation:

Let the length of the rectangle be equal to x

The width of a rectangle is 7 meters greater than its length. This would be expressed as

Width of rectangle = x+ 7

If the area of the rectangle is 170 square meters, then it is expressed as

Area of rectangle = Length × Width

x(x+7) = 170

The quadratic equation in standard form for the equation that would represent the area of the rectangle is

x^2 +7x=170

x^2 +7x- 170 = 0

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Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

5 0
3 years ago
Could I have some help on my patterns assignment​
nydimaria [60]

Answer:

1. 13, 18, 23, 28, 33, 38, 43, 48, 53

<em>Conjecture:</em> Each term is 5 more than the previous term.

2. 512, 256, 128, 64, 32, 16, 8, 4, 2

<em>Conjecture:</em> Each term is half of the previous term.

3. 1, 8, 27, 64, 125, 216, 343, 512, 729

<em>Conjecture:</em> Each term is a cube. To find the nth term, cube n.

4. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

<em>Conjecture:</em> Each term is the next consecutive prime number.

5. <u><em>Correct as is</em></u>

6. 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89

<em>Conjecture:</em> Each term is the sum of the 2 previous numbers.

Step-by-step explanation:

1.

Given: 13, 18, 23, 28

<em>We add 5 to each number</em>

13 + 5 = 18

18 + 5 = 23

23 + 5 = 28

28 + 5 = 33

33 + 5 = 38

38 + 5 = 43

43 + 5 = 48

48 + 5 = 53

2.

Given : 512, 256, 128, 64

<em>Divide each number by 2</em>

512 ÷ 2 =256

256 ÷ 2 = 128

128 ÷ 2 = 64

64 ÷ 2 = 32

32 ÷ 2 = 16

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

3.

Given: 1, 8, 27, 64

<em>We have to cube n:</em>

<u><em>n³ = consecutive number cubed</em></u>

<u><em></em></u>

1³ = 1 or 1 × 1 × 1

2³ = 8 or 2 × 2 × 2

3³ = 27 or 3 × 3 × 3

4³ = 64 or 4 × 4 × 4

5³ = 125 or 5 × 5 × 5

6³ = 216 or 6 × 6 × 6

7³ = 343 or 7 × 7 × 7

8³ = 512 or 8 × 8 × 8

9³ = 729 or 9 × 9 × 9

4.

Consecutive prime number: <u><em>Consecutive prime numbers are those that have no gaps or prime numbers between them.</em></u>

Look at the picture in the link:

6.

Given: 1, 1, 2, 3, 5, 8

<em>We must add the two previous numbers to get the next term:</em>

1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

3 + 5 = 8

5 + 8 = 13

8 + 13 = 21

13 + 21 = 34

21 = 34 = 55

34 + 55 = 89

8 0
1 year ago
PLEASE HELP!!! DONT IGNORE ME!!!
MrRa [10]
1. 2x^2-x-15=0
A = 2
B = -1
C = -15

2. 10^2-2x=0
A = 10
B = -2
C = 0

3. x^2–3x-40=0
A = 1
B = -3
C = -40

4. x^2+3x-2=0
A = 1
B = 3
C = -2

5. 4x^2-17x+8=0
A = 4
B = -17
C = 8

Remember the equations should look like Ax^2+Bx+C=0 (in this order!!)
5 0
3 years ago
A $15,000, 6 percent , 50-day note ,dated November 8, is discounted at 5 percent on November 28, the proceeds of the note would
tatyana61 [14]
The answer is the D option.
5 0
3 years ago
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Solve this please…..
Paraphin [41]

Answer:

17,12,15,14,12 answer 90

6 0
2 years ago
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