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andre [41]
4 years ago
12

We know that one mole of Oxygen gas contains two moles of O atoms (remember that O is a diatomic element in nature and is writte

n O2). If we have a sample of O2 that contains 1.0000 x 10-20 mol, we will have (blank)
atoms of O in the sample.
Chemistry
1 answer:
tatiyna4 years ago
6 0

Answer:

12.4 × 10∧3 atoms

Explanation:

Given data:

moles of oxygen molecule= 1.0000 x 10-20 mol

atoms =?

Solution:

32 g O2 = 1 mol = 6.02 × 10∧23

1.0000 x 10∧-20 mol × 6.02 × 10∧23 × 2 = 12.4 × 10∧3 atoms

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Several properties of the element magnesium are shown. Which one is a chemical property?
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E

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burning a substance changes it chemically.

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the molecules of water contracts when it is frozen

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3 years ago
When 429 mmhg of argon, 1.2 atm of neon, and 225 mmhg of helium are mixed, what is the total pressure?
Dmitry_Shevchenko [17]

The total pressure  1566 mm Hg.

Pressure is the force applied perpendicular to the floor of an object per unit location over which that pressure is shipped. Gauge strain additionally spelled gage pressure is the pressure relative to the ambient stress. pressure.

The SI unit of stress is pascal which is identical to one newton in keeping with rectangular meter. apparently, this name was given in 1971. earlier than that pressure in SI became measured in newtons in line with square meter.

Partial pressure of Argon = 429 mm Hg

Partial pressure of Neon = 1.2 atm

   ∵ 1 atm = 760 mm Hg

=> 1.2 atm = 1.2 * 760 mm Hg

                 = 912 mm Hg

Partial presser of He = 225 mm Hg

S0, Total pressure = Par + P ne + P he

                              =  ( 429 + 912 + 225 ) mm Hg

                              = 1566 mm Hg

Learn more about pressure here:-brainly.com/question/25965960

#SPJ4

6 0
1 year ago
Nitrogen gas and chlorine gas will react to form nitrogen monochloride gas. 5 moles of nitrogen and 10 moles of chlorine are mix
raketka [301]

Answer:

0.30

Explanation:

Step 1: Calculate the known initial and equilibrium molar concentrations

[N₂]i = 5 mol/2 L = 2.5 M

[Cl₂]i = 10 mol/2 L = 5 M

[NCl]e = 3 mol/2 L = 1.5 M

Step 2: Make an ICE chart

        N₂(g) + Cl₂(g) ⇄ 2 NCl(g)

I         2.5       5                0

C        -x        -x              +2x

E      2.5-x    5-x               2x

Step 3: Find the value of x

We know that [NCl]e = 2x = 1.5 ⇒ x = 0.75 M

Step 4: Calculate the concentrations at equilibrium

[N₂]e = 2.5-x = 2.5-0.75 = 1.75 M

[Cl₂]e = 5-x = 5-0.75 = 4.25 M

[NCl]e = 1.5 M

Step 5: Calculate the equilibrium constant (Kc)

Kc = [NCl]² / [N₂] × [Cl₂]

Kc = 1.5² / 1.75 × 4.25 = 0.30

7 0
3 years ago
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