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4 years ago

10

MATH PLS HELP EXAMS PROBLEM 1!!!!!!

1 answer:

STALIN [3.7K]4 years ago

3 0

Answer:

C) -12y-8y-4

Step-by-step explanation:

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The USDA reported that in 1990 each person in the United States consumed an average of 133 pounds of natural sweeteners. They al

blsea [12.9K]

Answer:

The problem implies that we want to write the (average) amount of natural sweeteners consumed per person as a function of time. Let y represent the (average) amount of natural sweeteners consumed per person (in pounds), and let x represent the time measured in years since 1990. That is, x = 0 represents 1990. If y is a linear function of x, then we can use the slope-intercept form y = mx + b (where m is the slope and b is the y-intercept) to write the function.

The slope can be interpreted as the rate of change of y with respect to x, which in this case means the change in consumption of natural sweeteners per year. The statement that consumption has decreased by 0.6 pounds per year tells us that the slope is m = -0.6 Also, the y-intercept is the same as the y-value of the function when x = 0. (In our case, that means time 0, that is, 1990.) Therefore the y-intercept is b = 133. Hope that helps! Let me know if you have any further questions.

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

For victoraa here is ur brainly my fellow....? oh human?

GarryVolchara [31]

Answer:

Well thanks for the points

Step-by-step explanation:

4 0

3 years ago

Joe's annual income has been increasing in the same dollar amount. The first year his income was $15,200, and the 4th year his i

lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

$A= P(1+\frac{r}{100} )^n$

$\Leftrightarrow 17900=15200(1+\frac{r}{100})^3$

$\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}$

$\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }$

$\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1$

$\Leftrightarrow r=5.60$

Let $t^{th}$ year Joe's income was $19,700.

$\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}$

$\Leftrightarrow 1.296= (1+0.056)^{t-1}$

$\Leftrightarrow 1.296= (1.056)^{t-1}$

$\Leftrightarrow log(1.296)= (t-1)log(1.056)$

$\Leftrightarrow \frac{log(1.296)}{log(1.056)}= (t-1)$

$\Leftrightarrow t-1= 4.75$

$\Leftrightarrow t= 4.75+1$

$\Leftrightarrow t = 5.75$ ≈6

Therefore 6th year his income was $19,700.

8 0

3 years ago

With regard to a regression-based forecast, the standard error of the estimate gives a measure of A. the variability around the

Travka [436]

Answer:

B. the variability around the regression line.

Step-by-step explanation:

The standard errors represents the distance (how sparse) the observed values fall from the regression line.

Standard errors for regression are measures of the spread of variables around the average (regression line)

The standard error is dependent on the standard deviation of the observations and the reliability of the test.

When the test is perfectly reliable, the standard error is zero and when unreliable, it is equal to the standard deviation of the observations.

8 0

3 years ago

What is the value of b 2 - 4ac for the following equation? 2x 2 3x = -1 0 1 17

sweet-ann [11.9K]

For 2x^2 + 3x = -1 => 2x^2 + 3x + 1 = 0 => a = 2, b = 3, c = 1
b^2 - 4ac = 3^2 - (4 x 2 x 1) = 9 - 8 = 1

4 0

4 years ago