We can use trial or error method here...
If we take 4 table, 4*5 = 20 and 4*7 = 28. 20+28 = 48.
20 : 28 = 5 : 7
So, there are 20 boys and 28 girls in a school play and there are 8 girls more than boys.
If you look over tables and try it out, only 4 table works for the given ratio.
Answer:
(1-cosA)/(1+cosA)
=(1-cosA)/(1+cosA) ×(1-cosA)/(1-cosA)
=(1-cosA)^2 /(1-cos^2A)
=(1-cosA)^2 / (sin^2A)
=(1/sinA - cosA/sinA )^2
=cosecA - cotA)^2
Hope it helps
Have a great Day ; )
Answer:
5 gallons of gas
Step-by-step explanation:
From the above question:
If:
80 miles = 4 gallons of gas
100 miles = x gallons of gas
Cross Multiply
80 × x = 100 × 4
x = 100 × 4/80
x = 5 gallons of gas
Therefore, Jackson would use 5 gallons of gas to get to Mount Highmore.
Answer:
Ticket price = $170
Number of tickets sold = 850
Step-by-step explanation:
Let X= the number of $10 price reduction and the number of 50 tickets increase
Let p= price per ticket
Let q= number of tickets sold
Let R= revenue
Let p(x) = price of ticket now sold
Let q(x) = number of tickets now sold
R(x) = p(x) * q(x)
P(x) = 300 - 10x
q(x)= 200 + 50x
R(x) = (300 -10x) (200 - 50x)
= 60000 + 15000x - 2000x - 500x^2
= 60000 + 13000x - 500x^2
Differentiate with respect to x
dR(x)/dx = 13000-1000x
Put dR(x)/dx = 0
0= 13000 - 1000x
1000x = 13000
Divide through by 1000
1000x/1000 = 13000/1000
x = 13
Therefore x = 13 for $10 price reduction and 50 tickets increase
p(x) = 300 - 10x
= 300 - 10*13
= 300 - 130
= $170
q(x) = 200 + 50x
= 200 + 50*13
= 200 + 650
= 650
Maximum Revenue = p(x) * q(x)
= 170 * 850
= $144,500
For 13 reductions, we have $170 price reduction and 850 ticket sales
9/20. Add 20+24+36=80. Then it's 36/80. Divide both the bottom and the top by 4 and you get 9/20.
