Question

Please answer ASAP.

Answer 1

Answer with explanation:

→The Smaller Quadrilateral called image is a dilation of Larger Quadrilateral ,having dilation factor less than 1.

→So,when image has smaller size than preimage,it means

 0< Dilation Factor <1

→Also,the Ratio of Corresponding sides,as well as area and perimeter of two Quadrilaterals will be congruent.

Dilation factor

$=\frac{8}{28}\\\\=\frac{2}{7}$

If 28,x,y and z are length of corresponding sides of larger Quadrilateral,that is pre image then 8, $\frac{2x}{7},\frac{2y}{7},\frac{2z}{7}$ are respectively corresponding side lengths of Image that is Smaller Quadrilateral.  

→→Ratio of the perimeter of pre image and Image

   $=\frac{28+x+y+z}{8+\frac{2x}{7}+\frac{2y}{7}+\frac{2z}{7}}\\\\=\frac{7\times(28+x+y+z)}{2\times(28+x+y+z)}\\\\=\frac{7}{2}$

→→Ratio of areas of two Quadrilateral ,that is pre image and Image

 =Square of Corresponding Side

$=\frac{28^2}{8^2}\\\\=\frac{784}{64}\\\\=\frac{49}{4}$

Option B

Answer 2

You will find the ratio of the perimeters by writing the length of 28 yards over 8 yards and simplifying it.

28/8 = 7/2

To find the ratio of the areas, you will multiply this by itself because there are two dimensions in an area.

7/2 x 7/2 = 49/4

The second choice is correct.