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Archy [21]
3 years ago
12

Count the number of 5-digit numbers (in the decimal system; integers from 10000 to 99999) which are not divisible by 11.

Mathematics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer:

So total number which is not divisible by 11 = 89999-8181 = 81819  

Step-by-step explanation:

We have to find the total numbers which are not divisible by 11 from 10000 to 99999

Total number from 10000 to 99999 = 99999-10000+1=90000

Just after 10000 the number which is divisible by 11 is 10010

And just below 99999 the number which is divisible by 11 is 99990

Using AP formula

T_N=a+(n-1)d, here a is first term, d is common difference and n is number of terms

So 99990=10010+(n-1)11

n-1 = 8180

n= 8181

So total number which is not divisible by 11 = 90000-8181 = 81819

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What is a numerical expression for the verbal expression. eight times six divided by two minus nine
Murljashka [212]

Answer:

(8x6)/2 + 9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(a) find the general solution to y^{\,\prime\prime} + 3 y^{\,\prime} = 0. give your answer as y = . . . \ . in your answer, use
KengaRu [80]
We want to solve
y'' + 3y' = 0

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Answer:
The general solution is
y(x) = c_{1} + c_{2}e^{-3x}

4 0
3 years ago
A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1
kvasek [131]

Answer:

CI=\{-0.2941,-0.0337\}

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is \displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2} where \hat{p}_1 and n_1 are the sample proportion and sample size of the first sample, and \hat{p}_2 and n_2 are the sample proportion and sample size of the second sample.

We see that \hat{p}_1=\frac{87}{249}\approx0.3494 and \hat{p}_2=\frac{58}{113}\approx0.5133. We also know that a 98% confidence level corresponds to a critical value of z^*=2.33, so we can plug these values into the formula to get our desired confidence interval:

\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

5 0
2 years ago
6n-3&gt;-18<br> Solve the inequality
Tamiku [17]

Answer:

<h3>n>-5/2</h3>

Step-by-step explanation:

First, you have to isolate it on one side of the equation. Remember that, isolate n on one side of the equation.

6n-3>-18

6n-3+3>-18+3 (Add 3 from both sides.)

-18+3 (Solve.)

-18+3=-15

6n>-15

6n/6>-15/6 (Divide by 6 from both sides.)

-15/6 (Solve.)

-15/6=-5/2

n>-5/2

In conclusion, the correct answer is n>-5/2.

3 0
3 years ago
−1.2(3x − 3) = 4(3x +0.9)<br><br><br> help pls
Viefleur [7K]

Answer:

- 1.2(3x - 3) = 4(3x + 0.9) \\  - 3.6x + 3.6 = 12x + 3.6 \\  12x + 3.6x = 3.6 - 3.6 \\ 15.6x = 0 \\  \\ x =  \frac{0}{15.6}  \\  \\ x = 0

I hope I helped you^_^

6 0
2 years ago
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